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Thepotemich [5.8K]
3 years ago
15

Help please! Thanks! :)

Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

57

Step-by-step explanation:

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Convert this Percent to a Decimal 56% <br> A:0.56<br> B: 56<br> C:5.6<br> D:.65 <br> TwT
kirill115 [55]

Answer:

A

Step-by-step explanation:

Move the decimal point 2 spaces to the left to convert from percent to decimal.

3 0
3 years ago
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What is the slope of the line that passes through the points ( 10 , − 6 ) (10,−6) and ( 8 , − 16 ) ? (8,−16)?
GaryK [48]

Answer:

5

Step-by-step explanation:

-16-(6)

over

8-10

slope= -10/-2

simplify:

5/1=5

4 0
3 years ago
Find domain of y=rad20-6x
Evgesh-ka [11]
Domain, on an "even root" context, means, an even root cannot have a negative radicand, since  say for example \bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x

now, if "x" is 10/3, let's see \bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example  \bf x=\frac{11}{3}&#10;\\\\\\&#10;&#10;\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish
5 0
4 years ago
Which is a factor of 10 but not a mutiple of 2? choices are 8,5,4,and 6
Verizon [17]

5 is Your answer,5 factors into 10 but none of the other choices do


8 0
3 years ago
Read 2 more answers
Find m∠TUL.
pogonyaev

 

Step-by-step explanation:

Actual graph for this problem is attached below

m∠TUV = 167°

m∠TUL = (x + 11)°

m∠LUV = (11x)°

m∠TUV= m∠TUL+ m∠LUV

now plug in the angles for each

m∠TUV= m∠TUL+ m∠LUV

167= x+11 +11x

solve the equation for x

167= x+11 +11x\\167=11 +12x

Subtract 11 from both sides

156=12x

divide both sides by 12

x=13

m∠TUL = (x + 11)°

m∠TUL = (13+ 11)° = (24)°

answer:

24°

4 0
3 years ago
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