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3 years ago

Perform the calculation then round of the appropriate number of significant digits 14.4 x 1.2

Mathematics

1 answer:

irakobra [83]3 years ago

4 0

17.00
because when you round, it is 5 or above your round up a digit. 4 or less you let it remain. I hope I helped.

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What is 2.8 as a fraction in simplest form

irina1246 [14]

2.8 = 2 + 0.8

*let's analyze the decimal 0.8 as a fraction

0.8 = 8/10

*but if we divide the numerator and denominator by the same common factor of 2, we find that the fraction can be reduced to:

(8/2)/(10/2) = (4)/(5) = 4/5

*now evaluating the whole value of 2 (from the 2.8), we know there are a total of (5) - fifths in order to make a whole, so for 2 whole, we require:

2*(5/5) = (2*5)/5 = 10/5

*Now we add the fractions together:

2 = 10/5
0.8 = 4/5

10/5 + 4/5

*add numerators only, the denominator stays as a 5

(10 + 4)/5 = 14/5

*there are no common factors between 14 & 5 (other than 1, but that won't help reduce the fraction any), so the fraction is in it's simplest form:

answer is: 14/5

8 0

3 years ago

Read 2 more answers

Katie gives Maggie half of her pencils. Maggie keeps 5 pencils and gives the rest to Jamil. A. Write an expression for the numbe

Alexandra [31]

Here's what I mean when I write x/2 JUST IN CASE.

а.

Let the total number of pencils be x, then this implies that Maggie received x/2 pencils from Katie. Maggie keeps 5 and give the rest to Jamil, this means

that Jamil receives

x/2-5 pencils.

b. Expression of pencils given to Jamil is: x/2-5

Substitute x=16 in this expression: x/2-5

Simplify and evaluate: = 8-5= 3

Maggie gives 3 pencils to Jamil.

c. Expression of pencils given to Jamil is: x/2-5 to

Equate this expression with 1 to form an equation and solve for x all, the total

number of pencils if Jamil received 1 pencil:

x/2 - 5 = 1

Solve for x:

x = 2(1+ 5)

Evaluate:

x = 2(6) = 12

Katie had 12 pencils if Jamil received 1 pencil.

RESULT

a. Expression of number of pencils given to Jamil is x/2-5, where x is total number of pencils.

b. Maggie gives 3 pencils to Jamil.

c. Katie had 12 pencils if Jamil received 1 pencil.

5 0

3 years ago

Please help, thank you so much !!

Sliva [168]

Answer: x = 54

Explanation:

180 - 14 = 166

3x + 4 = 166
3x = 162
x = 162/3 = 54

6 0

2 years ago

The average weight of 3 containers A,B and C is 3.2kg. Container A is twice as heavy as container B. Containers B is 400 g heavi

dlinn [17]

Answer:

The weight of container C is 2.1kg.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the weight of container A.

y is the weight of container B.

z is the weight of container C.

The average weight of 3 containers A,B and C is 3.2kg.

This means that the total weight is 3*3.2 = 9.6kg. So

$x + y + z = 9.6$

Container A is twice as heavy as container B.

This means that $x = 2y$ .

Containers B is 400 g heavier than container C.

400g is 0.4kg. So

This means that $y = z + 0.4$ , or $z = y - 0.4$

Replacing y and z as functions of x in the first equation:

$x + y + z = 9.6$

$2y + y + y - 0.4 = 9.6$

$4y = 10$

$y = \frac{10}{4} = 2.5$

Container C

$z = y - 0.4 = 2.5 - 0.4 = 2.1$

The weight of container C is 2.1kg.

4 0

3 years ago

What eigen value for this matix (1 -2) (-2 0)

natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

Compute the matrix $A' = A-\lambda I$ , where I is the identity matrix (1s on the diagonal, 0s elsewhere)
Compute the determinant of A'
Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

$A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]$

The determinant of this matrix is

$\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4$

Finally, we have

$\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}$

So, the two eigenvalues are

$\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}$

5 0

3 years ago

Read 2 more answers