Please help me with the one in the middle

Warm Up Quiz 1. What is the Net Force acting on an object that contains: Fg=2 N, Fn=2 N, Fa=12 N and Ff=2 N?

Kay [80]

Answer:

one that acts in the direction of the acceleration is the static friction force. The ... Express fs,max in terms of Fn in the x ... ma. FF = − g n. Fn − w = may = 0 or, because ay = 0 and Fg = mg, mg. F = n.

5 0

3 years ago

Student in ms sawyers class built balloon cars the balloon car works this way as the gas in the balloon is released the car move

RUDIKE [14]

Answer:

Third Law of Motion

Explanation:

7 0

3 years ago

an object is shot vertically upward into the air with an initial velocity of 20 m/s? which of the following correctly describes

Drupady [299]

Answer:

Answer is (C)

Explanation:

For acceleration

• If the motion is vertically, then acceleration is 9.8 m/s²

» Upward motion, acceleration is negative (-9.8)

» Downward motion, acceleration is positive (+9.8)

For velocity

${ \rm{v = u + gt}} \\ { \rm{v = 20 + ( - 9.8 \times 4)}} \\ { \rm{v = - 19.2 \: m {s}^{ - 1} }}$

5 0

2 years ago

(7)Figure 4 shows three charges: Q₁, Q₂ and Q3 . Determine the net force (Fnet) acting on Q3. (Hint: Draw a free body diagram of

NISA [10]

Remember Coulomb's law: the magnitude of the electric force F between two stationary charges q₁ and q₂ over a distance r is

$F = \dfrac{kq_1q_2}{r^2}$

where k ≈ 8,98 × 10⁹ kg•m³/(s²•C²) is Coulomb's constant.

8.1. The diagram is simple, since only two forces are involved. The particle at Q₂ feels a force to the left due to the particle at Q₁ and a downward force due to the particle at Q₃.

8.2. First convert everything to base SI units:

0,02 µC = 0,02 × 10⁻⁶ C = 2 × 10⁻⁸ C

0,03 µC = 3 × 10⁻⁸ C

0,04 µC = 4 × 10⁻⁸ C

300 mm = 300 × 10⁻³ m = 0,3 m

600 mm = 0,6 m

Force due to Q₁ :

$F_{Q_2/Q_1} = \dfrac{k (6 \times 10^{-16} \,\mathrm C)}{(0,3 \, \mathrm m)^2} \approx \boxed{6,0 \times 10^{-5} \,\mathrm N} = 0,06 \,\mathrm{mN}$

Force due to Q₃ :

$F_{Q_2/Q_3} = \dfrac{k (12 \times 10^{-16} \,\mathrm C)}{(0,6 \, \mathrm m)^2} \approx \boxed{3,0 \times 10^{-5} \,\mathrm N} = 0,03 \,\mathrm{mN}$

8.3. The net force on the particle at Q₂ is the vector

$\vec F = F_{Q_2/Q_1} \, \vec\imath + F_{Q_2/Q_3} \,\vec\jmath = \left(-0,06\,\vec\imath - 0,03\,\vec\jmath\right) \,\mathrm{mN}$

Its magnitude is

$\|\vec F\| = \sqrt{\left(-0,06\,\mathrm{mN}\right)^2 + \left(-0,03\,\mathrm{mN}\right)^2} \approx 0,07 \,\mathrm{mN} = \boxed{7,0 \times 10^{-5} \,\mathrm N}$

and makes an angle θ with the positive horizontal axis (pointing to the right) such that

$\tan(\theta) = \dfrac{-0,03}{-0,06} \implies \theta = \tan^{-1}\left(\dfrac12\right) - 180^\circ \approx \boxed{-153^\circ}$

where we subtract 180° because $\vec F$ terminates in the third quadrant, but the inverse tangent function can only return angles between -90° and 90°. We use the fact that tan(x) has a period of 180° to get the angle that ends in the right quadrant.

8 0

2 years ago

Explain how the lithosphere, hydrosphere, and atmosphere individually and collectively affect the biosphere. (2 points)

SSSSS [86.1K]

Answer:

The hydrosphere, the sphere of influence that deals with water in its various forms (some separate out ice and call that the cryosphere), provides the biosphere with a much needed component....water. Life would not exist as we know it without water. It places in important role for all organisms, alongside playing an important role in various earth processes.

Explanation:

6 0

3 years ago