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liubo4ka [24]
2 years ago
14

Every second, the Sun converts about 600 million tons of hydrogen into 596 million tons of helium. The remaining 4 million tons

of mass is Every second, the Sun converts about 600 million tons of hydrogen into 596 million tons of helium. The remaining 4 million tons of mass is converted to an amount of energy equal to 4 million tons times the speed of light cubed. converted to an amount of energy equal to 4 million tons times the speed of light. reabsorbed as molecular hydrogen. converted to an amount of energy equal to 4 million tons times the speed of light squared. ejected into space in a solar wind.
Physics
1 answer:
Whitepunk [10]2 years ago
4 0

Answer:

Converted to an amount of energy equal to 4 million tons times the speed of light squared. ejected into space in a solar wind.

Explanation:

The 4 million tons of mass is converted to the amount of energy that is equal to 4 million tons times the speed of light squared. This energy moves from the sun with the help of solar winds and received by the planets present in the solar system. This solar energy moves in the form of solar radiation because there is no medium for propagation so that's why we can say that the mass is converted into energy that moves in the form of radiation in discrete packets.

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<span> Weight = mass x acceleration
Earths acceleration is 9.8 m/s*2
1 kg = 2.2 lbs, so 2.0 lbs x 1 kg/2.2 lbs = 0.91 kg
The bag would have a weight of 9.8 x 0.91 = 8.9 N

1. 8.9 x 1/6 = 1.5 N

2. 8.9 x 2.64 = 23.5 N

The mass of the bag at all three locations is 0.91 kg. Mass does not change, the different locations only change its weight. </span>
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C gains potential energy
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4 0
3 years ago
The velocity of the transverse waves produced by an earthquake is 8.9 km/s, and that of the longitudinal waves is 5.1 km/s. A se
Brrunno [24]

Answer: The distance is 723.4km

Explanation:

The velocity of the transverse waves is 8.9km/s

The velocity of the longitudinal wave is 5.1 km/s

The transverse one reaches 68 seconds before the longitudinal.

if the distance is X, we know that:

X/(9.8km/s) = T1

X/(5.1km/s) = T2

T2 = T1 + 68s

Where T1 and T2 are the time that each wave needs to reach the sesmograph.

We replace the third equation into the second and get:

X/(9.8km/s) = T1

X/(5.1km/s) = T1 + 68s

Now, we can replace T1 from the first equation into the second one:

X/(5.1km/s) = X/(9.8km/s) + 68s

Now we can solve it for X and find the distance.

X/(5.1km/s) - X/(9.8km/s) = 68s

X(1/(5.1km/s) - 1/(9.8km/s)) = X*0.094s/km= 68s

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6 0
3 years ago
What's the time constant of a 10 H inductor and a 200 ohm resistor connected in series
melamori03 [73]
<h3>Option B</h3><h3>The time constant of a 10 H inductor and a 200 ohm resistor connected in series is 50 millisecond</h3>

<em><u>Solution:</u></em>

Given that,

10 H inductor and a 200 ohm resistor connected in series

To find: time constant

<em><u>The time constant in seconds is given as:</u></em>

Time\ constant = \frac{L}{R}

Where,

L is the inductance in henry and R is the resistance in ohms

Time\ constant = \frac{10}{200}\\\\Time\ constant = 0.05\ seconds

Convert to millisecond

1 second = 1000 millisecond

0.05 second = 0.05 x 1000 = 50 millisecond

Thus time constant is 50 millisecond

7 0
3 years ago
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