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juin [17]
1 year ago
12

Find the momentum (in kg m/s) for a 1.6 kg brick parachuting straight downward at a constant speed of 9.9 m/s.

Physics
1 answer:
tangare [24]1 year ago
4 0

The momentum of the brick is 15.84 Kg m/s.

We have a 1.6 kg brick parachuting straight downward.

We have to determine its Momentum.

<h3>What is Linear Momentum ?</h3>

The linear momentum of a body of mass M moving with velocity v is -

p = mv.

According to the question -

Mass = 1.6 Kg

Velocity = 9.9 m/s

Therefore -

p = 1.6 x 9.9 = 15.84 Kg m/s

Hence, the momentum of the brick is 15.84 Kg m/s.

To solve more questions on Linear Momentum, visit the link below-

brainly.com/question/12057523

#SPJ1

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A 1400-kg car is traveling with a speed of 17.7 m/s. What is the magnitude of the horizontal net force that is required to bring
AleksandrR [38]

Answer:

The magnitude of the horizontal net force is 13244 N.

Explanation:

Given that,

Mass of car = 1400 kg

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v^2-u^2=2as

Where, u = initial velocity

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s = distance

Put the value in the equation

0-(17.7)^2=2a\times 33.1

a=\dfrac{-(17.7)^2}{33.1}

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Negative sign shows the deceleration.

We need to calculate the net force

Using newton's formula

F = ma

F =1400\times(-9.46)

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Negative sign shows the force is opposite the direction of the motion.

The magnitude of the force is

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Hence,  The magnitude of the horizontal net force is 13244 N.

5 0
3 years ago
A cart for hauling ore out of a gold mine has a mass of 413 kg, including its load. the cart runs along a straight stretch of tr
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Given from the problem :mass m = 413 kg;coefficient of friction u = 0.0163;acceleration due to gravity g = 9.8 m/s2;inclined angle @1 = 14.3;inclined angle  @2 = 4.69;distance travelled d = 175 m;applied fore F = 410 N;  the component of the force from the donkey in the direction of motion isF2 = F1 [email protected]= 397.2964498768165 N
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F2 - mg [email protected] - f = maa = F2 - mg [email protected] - f/ m=0.31923412183075155 m/s^2
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