Answer:
2
Step-by-step explanation:
the answer is 2 ..........
Hi! Multiply -0.25 by the inner numbers.
-0.25 times 84 = 21
-0.25 times -32n = -8n
Then take the -n and add that
21 -8n - n
-8n - n (or -1n) = -9n
therefore, answer would be a) 21 - 9n
If xy=0 assume that x and y=0
so
(2x-8)(7x+5)=0
assume
2x-8=0 and 7x+5=0
solve each
2x-8=0
2x=8
x=4
7x+5=0
7x=-5
x=-5/7
so x=-5/7 or 4
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
