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2 years ago

17/5 converted into a mixed number

Mathematics

2 answers:

meriva2 years ago

5 0

Answer:

3 2/5

Step-by-step explanation:

Mila [183]2 years ago

3 0

Answer:

3 $\frac{2}{5}$

Step-by-step explanation:

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? Don't Send links, don't Write random things and get the points for free.

alekssr [168]

Answer:

$V = 1847.26\ ft^3$

Step-by-step explanation:

Step 1: Determine the volume

$V=\pi r^2h$

$V = \pi *(7\ ft)^2 * (12\ ft)$

$V = \pi *49\ ft^2 * 12\ ft$

$V = \pi * 588\ ft^3$

$V = 1847.26\ ft^3$

Answer: $V = 1847.26\ ft^3$

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%7Cx-%5Cfrac%7B1%7D%7B2%7D%7C%3D3%5Cfrac%7B2%7D%7B3%7D" id="TexFormula1" title="|x-\frac{1}{2}

Bogdan [553]

Answer:

x= 4 1/6, -3 1/6

Step-by-step explanation:

Hope this helps

8 0

2 years ago

Read 2 more answers

Drag each number to the correct location on the table.

ASHA 777 [7]

Answer:

$\text{Rational number} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ Irrational number}$

$3\sqrt{25} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \sqrt{141}\\\\\sqrt{256} \\\\1. \overline{ 1625} \\\\\frac{-11}{151}$

Step-by-step explanation:

Since we believe it

The number sequence is that those which can be described as $\frac{p}{q}$ and that is not ending and recurring. Figures that are unreasonable are also the ones, that are not $\frac{p}{q}$ and therefore are non-ending, non-recurring.

The number sequence is $3\sqrt{25} = 3 \times 5 = 15$

Rational amount since it is classified as $\frac{p}{q}$ . $\frac{-11}{151}$ is really a rational number.

$1.\overline{1.625}$ is a real function, since it does not end but repeats it.

The rational number $\sqrt {256} = 16$

Unreasonable number $\sqrt{141}$ .

7 0

3 years ago

Read 2 more answers

PLEASE HELP

dsp73

Answer:

All events are independent

Step-by-step explanation:

You are given the table

$\begin{array}{cccc}&\text{Chocolate}&\text{Vanilla}&\text{Total}\\\text{Adults}&0.21&0.39&0.60\\\text{Children}&0.14&0.26&0.40\\\text{Total}&0.35&0.65&1.00\end{array}$