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2 years ago

Solve the system of equations -2x+y=5 x-3y=-30

1 answer:

5 0

-2x+y=5
x-3y=-30 so you can multiply the bottom equation by 2 you'll get 2x-6y=-60

-2x+y=5
2x-6y=-60 And subtract the equations. You'll get -5y=-55 y=11. Plug it in to one of the original equations. -2x+(11)=5
-2x=-6 so x=3

y=11 and x=3

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A line has a slope of -13. There is a second line that passes through points (-7,-5) and (6,-4) . Would these lines be parallel

Elza [17]

<h3>Answer: The lines are perpendicular</h3>

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Work Shown:

Use the slope formula to find the slope of the line through the two given points.

m = (y2 - y1)/(x2 - x1)

m = (-4 - (-5))/(6 - (-7))

m = (-4 + 5)/(6 + 7)

m = 1/13

The slope of the line through the two given points is 1/13.

This is not equal to -13, which was the slope of the first line, so the two lines are not parallel.

However, the two lines are perpendicular because multiplying the two slope values leads to -1

(slope1)*(slope2) = (-13)*(1/13) = -1

note: It might help to think of -13 as -13/1 to help multiply the fractions.

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Alternative hypothesis [tex]\mu \neq 1.7[/tx]

And the best system of hypothesis are:

3. This two-sided test:

H0: μ = 1.7 mm

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