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Viktor [21]
3 years ago
14

A lab technician mixed a 540 ml solution of water and alcohol. if​ 3% of the solution is​ alcohol, how many milliliters of alcoh

ol were​ used, and how many milliliters of water were​ used?
Chemistry
1 answer:
DochEvi [55]3 years ago
7 0
3% = 0.3
.03*540 = 16.2
540-16.2 = 523.8

Meaning 16.2 milliliters alcohol and 523.8 milliliters water. If my math is correct.

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A burner on a stove produces temperature. thermal energy. hotness. fire energy.
Aleksandr [31]

Question:

The options are;

a. Temperature

b. Thermal Energy

c. Hotness

d. Fire Energy

Answer:

The correct option is;

b. Thermal energy

Explanation:

A burner on a stove produces thermal energy which is used to raise the temperature of the metal container (kettle, pot or pans) in which items are placed for heating.

Thermal energy is the internal energy of the system given off as heat which when transferred from one body to another causes the temperature of the receiving body to rise. Thermal energy in a burner is given off when the gaseous fuel reacts or burns in the presence of or with oxygen to produce carbon dioxide and water vapor in an exothermic reaction.

4C + 5H₂ + 13/2O₂ (-125 kJ) → C₄H₁₀ + O₂ → CO₂ + H₂O (-2877 kJ).

4 0
4 years ago
Read 2 more answers
Given the following two quantities: 0.50 mol of CH4 and 1.0 mol of HCl,
Vinil7 [7]

Answer:

(a) HCl

(b) HCl

(c) HCl

(d) HCl

Explanation:

<em>Given: </em>0.50 mol of CH₄ and 1.0 mol of HCl

Using stoichiometry we can calculate the answers to parts a, b, c, and d.

<h3>Part (a) </h3>

# of moles × Avogadro's number = # of atoms or molecules

Avogadro's number: 6.02 * 10²³

  • \displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{6.02\cdot 10^2^3 \ \text{atoms CH}_4}{1 \ \text{mol CH}_4} = 3.01 \cdot 10^2^3 \ \text{atoms CH}_4
  • \displaystyle 1.0\ \text{mol HCl} \cdot \frac{6.02\cdot 10^2^3 \ \text{atoms HCl}}{1 \ \text{mol HCl}} = 6.02 \cdot 10^2^3 \ \text{atoms HCl}

HCl has more atoms than CH₄.

<h3>Part (b) </h3>

This is calculated the same way as Part (a); HCl has more molecules than CH₄.

<h3>Part (c) </h3>

Molar mass of CH₄ = 16.04 g/mol

Molar mass of HCl = 36.458 g/mol

  • \displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{16.04 \ \text{g CH}_4}{1 \ \text{mol CH}_4} = 8.02 \ \text{g CH}_4
  • \displaystyle 1.0\ \text{mol HCl} \cdot \frac{36.458 \ \text{g HCl}}{1 \ \text{mol HCl}} = 36.458 \ \text{g HCl}

HCl has a greater mass than CH₄.

<h3>Part (d)</h3>

Assuming STP:

Molar volume of any gas at STP is 22.4 L/mol.

  • \displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{22.4 \ \text{L CH}_4}{1 \ \text{mol CH}_4} = 11.2 \ \text{L CH}_4
  • \displaystyle 1.0\ \text{mol HCl} \cdot \frac{22.4 \ \text{L HCl}}{1 \ \text{mol HCl}} = 22.4 \ \text{L HCl}

HCl has a greater volume than CH₄.

5 0
3 years ago
Which half-reaction is most easily reduced? Al3+ + 3e- Al = -1.66 V Cu2+ + 2e- Cu = 0.34 V Fe3+ + e- Fe2+ = 0.77 V Na+ + e- Na =
Rom4ik [11]
<span />The answer is <span>Fe3+ + e- Fe2+ =</span>
6 0
4 years ago
Read 2 more answers
NaOH
KIM [24]

Answer:

i have no idea and i dont get it

7 0
3 years ago
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Plsss help <br> will mark BRAINLIEST
satela [25.4K]

Answer:

c

Explanation: just a chemachal

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3 years ago
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