Answer:
(a) HCl
(b) HCl
(c) HCl
(d) HCl
Explanation:
<em>Given: </em>0.50 mol of CH₄ and 1.0 mol of HCl
Using stoichiometry we can calculate the answers to parts a, b, c, and d.
<h3>Part (a) </h3>
# of moles × Avogadro's number = # of atoms or molecules
Avogadro's number: 6.02 * 10²³
HCl has more atoms than CH₄.
<h3>Part (b) </h3>
This is calculated the same way as Part (a); HCl has more molecules than CH₄.
<h3>Part (c) </h3>
Molar mass of CH₄ = 16.04 g/mol
Molar mass of HCl = 36.458 g/mol
HCl has a greater mass than CH₄.
<h3>Part (d)</h3>
Assuming STP:
Molar volume of any gas at STP is 22.4 L/mol.
HCl has a greater volume than CH₄.