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7nadin3 [17]
3 years ago
13

Plsss help will mark BRAINLIEST

Chemistry
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

c

Explanation: just a chemachal

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elixir [45]

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yes

Explanation:

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2 years ago
Identify the reactants and the products of the preparation step to the urea cycle.
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7 0
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What volume of concentrated (10.2 M) HCl would be required to prepare 1.11 x 104 mL of 1.5 M HC1? Enter your answer in scientifi
Tomtit [17]

Answer:

The required volume is 1.6 x 10³mL.

Explanation:

When we want to prepare a dilute solution from a concentrated one, we can use the dilution rule to find out the required volume to dilute. This rule states:

C₁ . V₁ = C₂ . V₂

where,

C₁ and V₁ are the concentration and volume of the concentrated solution

C₂ and V₂ are the concentration and volume of the dilute solution

In this case, we want to find out V₁:

C₁ . V₁ = C₂ . V₂

V_{1} = \frac{C_{2}.V_{2}}{C_{1}} = \frac{1.5M \times1.11.10^{4}mL }{10.2M} =1.6\times10^{3} mL

3 0
3 years ago
What is the mass of a block with a volume of 18 cm^3, and a density of 9.2 g/cm^3?
Semmy [17]

Answer: 165.6grams

Explanation:

Mass of a block = ?

Volume of block = 18 cm^3

Density of block = 9.2 g/cm^3

The density of any object depends on its mass and volume.

i.e Density of block = Mass / volume

9.2 g/cm^3 = Mass / 18 cm^3

Mass = 9.2 g/cm^3 x 18 cm^3

= 165.6 g

Thus, the mass of the block is 165.6grams

6 0
3 years ago
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