Draw the products obtained from the reaction of 1 equivalent of HBr with 1 equivalent of 2,5-dimethyl-1,3,5-hexatriene. Draw the
molecules on the canvas by choosing buttons from the Tools (for bonds and charges), Atoms, and Templates toolbars
1 answer:
Answer:
Here's what I get.
Explanation:
According to Markovnikov's rule, the H will add to a terminal carbon, generating three resonance stabilized carbocations.
The Br⁻ ion will add to any of the three carbocations.
There are three possible products:
- 5-bromo-2,5-dimethylhexa-1,3-triene (1)
- 3-bromo-2,5-dimethylhexa-1,4-triene (<em>2</em>)
- 1-bromo-2,5-dimethylhexa-2,4-triene (3)
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Answer:
The correct answer is option B.
Explanation:
Michaelis–Menten 's equation:
v = rate of formation of products
[S] = Concatenation of substrate = ?
= Michaelis constant
= Maximum rate achieved
= Catalytic rate of the system
= initial concentration of enzyme
We have :
[S] =?
So, the correct answer is option B.
Answer:
- <u><em>g) Neither plant should increase by 1 cm in height.</em></u>
Explanation:
See the graph for this question on the figure attached.
The growing of the <em>plant A</em> is represented by the line that goes above the other. At start, that line has a slope that rises about 0.75 cm ( height increase) in 1 day. From the day 2 and forward the slope of the line decreases. The line reaches its highest point about at day 4 and seems to start decreasing. Thus, you should predict that on the day six it <em>most likely </em>does not increase in height.
The growing of the <em>plant B</em> is represented by the line drawn below the other. As for the plant B, the growing decreases with the number of days. Between the days 4 and 5 the line is almost flat, which means that <em>most likely</em> this plant will not grow on the day six or grow less than 0.5 cm.
Thus, for both plants you can say that <em>on day six, most likley, neither should increase by 1 cm in height (</em>option g).
