The question asks that you use algebra tiles to model and solve the equation
. I set up the scenario digitally (see attached image).
Whatever blocks you have on both sides you can cancel. So we cancel one
-block, and to take away the
-block, we balance the equation by putting a
-block on the other side. We are left with 2
-blocks equal to 6
-blocks. This is equivalent to 1
-bock equal to 3
blocks, so
.
Algebraically, you can write
.
I personally find the latter approach much easier, but I think the tiles are a nice way to conceptualize what you're doing.