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Ugo [173]
3 years ago
13

(x-8) (2x +9)

Mathematics
1 answer:
nika2105 [10]3 years ago
8 0

im not being rude i was just trying yo say sais the Anser but.it wouldnt let mr so now im sad

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An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.
Greeley [361]

Answer: 1) 0.6561    2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

P(X=x)=^nC_xp^x(1-p)^{n-x}

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel.  : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}

=(1)(0.90)^4=0.6561

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0
3 years ago
Rachel recorded the number of calls she made at work during the week:
Dmitry [639]

The chi-squared test statistic will be 3.11. The test statistic is contrasted with a predicted value based on the Chi-square distribution.

<h3>What is the chi-squared test statistic?</h3>

Finding the squared difference between the actual and anticipated data values, then dividing that difference by the expected data values, constitutes the test statistic.

The formula for the chi-squared test statistic is;

\sum \frac{(O_i-E_i)^2}{E_i } \\\\

Where,

\rm O_i is the observed value

\rm E_i is the expected value

The chi-square test statics is;

\rm( \frac{18-18}{18} )^2 +( \frac{14-18}{18} )^2 + (\frac{24-18}{18} )^2+( \frac{16-18}{18} )^2 \\\\ 0+ \frac{16}{18}+ \frac{36}{18} +\frac{4}{18}\\\\ \frac{56}{18} \\\\ 3.11

Hence, the chi-squared test statistic will be 3.11.

To learn more about the chi-squared test statistic refer;

brainly.com/question/14082240

#SPJ1

5 0
2 years ago
Helppp me asap! plssss
zzz [600]

Answer 5x 1y 5 1

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Sam made $210.00 last week. If he worked 35 hours, how much is he paid for one hour of work?
saw5 [17]

Answer:

6 bucks

Step-by-step explanation:

210/35 = 6

210 dollars/ 35 hours = 6 dollars er hour

3 0
3 years ago
Read 2 more answers
Jose bought 3 pens and 6 pencils for $6.60. Amy bought 5 pens and 8 pencils for $10.00. How much does one pencil cost?
xenn [34]

Answer:

pen = $1.20,  pencil = $0.50

Step-by-step explanation:

let x = pen

let y = pencil

create system of equations:

3x + 6y = 6.60        [can be simplified to be x + 2y = 2.20]

5x + 8y = 10.00

substitution method:

x = 2.2 - 2y

5(2.2 - 2y) + 8y = 10

11 - 10y + 8y = 10

-2y = -1

y = 1/2

solve for 'x':

3x + 6(1/2) = 6.6

3x + 3 = 6.6

3x = 3.6

x = 1.2

7 0
2 years ago
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