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nydimaria [60]
2 years ago
12

Plz help due tomorrow

Mathematics
2 answers:
Juli2301 [7.4K]2 years ago
6 0

Answer:

11.2 - 10y

Step-by-step explanation:

= 4-3y +(-7y) + 7.2

= 4 -3y -7y +7.2

= 4 -10y +7.2

= 4 +7.2 - 10y

= 11.2 - 10y

luda_lava [24]2 years ago
4 0

Answer:

4-3y+(-7y)+7.2

4-3y+-7y+7.2

11.2-3y-7y

11.2=10yu

Step-by-step explanation:

hope you like my answer

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What is the area of the trapezoid?
Maslowich
<h3><u>Given Information :</u></h3>

  • Length of parallel sides = 60 ft and 40 ft
  • Height of the trapezoid = 30 ft

<h3><u>To calculate :</u></h3>

  • Area of the trapezoid.

<h3><u>Calculation :</u></h3>

As we know that,

\bigstar \: \boxed{\sf {Area_{(Trapezium)} = \dfrac{1}{2} \times ( a + b) \times h}} \\

  • a and b are length of parallel sides.
  • h denotes height.

<em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>valu</em><em>es</em><em>,</em><em> </em><em>we</em><em> </em><em>get</em><em> </em>:

\longmapsto Area = \sf \dfrac{1}{2} × ( 60 + 40 ) × 30 ft\sf ^2

\longmapsto Area = \sf \dfrac{1}{2} × 100 × 30 ft\sf ^2

\longmapsto Area = 1 × 100 × 15 ft\sf ^2

\longmapsto Area = 100 × 15 ft\sf ^2

\longmapsto <u>Area = 1500 ft</u>\sf ^2

Therefore,

  • Area of the trapezoid is <u>1500 ft\sf ^2</u>

6 0
2 years ago
A local technical school has 856 students. They expect 700 guests for a special speaker. The custodian has set up 1,500 chairs.
Delicious77 [7]

Answer:

56 chairs

Step-by-step explanation:

856+700=1556    <--- expected count

chairs set up= 1500

1556-1500= 56 more chairs

4 0
3 years ago
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xenn [34]

Answer:

2 x minus y = negative 6 and 3 x minus y = negative 5

Step-by-step explanation:

y = 2(x+3) = 2x + 6 or 2x - y = -6

y = 5 + 3x or 3x - y = -5

7 0
3 years ago
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Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F'G'H'I':
SVETLANKA909090 [29]

Answer:

(x, y)→(x − 8, y − 7)

Step-by-step explanation:

If we take the hexagon DEFGHI coordinates and apply the rule (x, y)→(x − 8, y − 7) we get:

D (2, 5) → (2 - 8, 5 - 7) = (-6, -2) which corresponds to point D'

E (5, 5) → (5 - 8, 5 - 7) = (-3, -2) which corresponds to point E'

F (6, 3) → (6 - 8, 3 - 7) = (-2, -4) which corresponds to point F'

G (5, 1) → (5 - 8, 1 - 7) = (-3, -6) which corresponds to point G'

H (2, 1) → (2 - 8, 1 - 7) = (-6, -6) which corresponds to point H'

I (1, 3) → (1 - 8, 3 - 7) = (-7, -4) which corresponds to point I'

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2 years ago
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Marat540 [252]
-5x+12 is the answer
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