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aalyn [17]
3 years ago
5

Calculate the cost for camping and the cost per night

Mathematics
1 answer:
cluponka [151]3 years ago
8 0
Rounded: 35.04

non rounded: 35.03
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If the principle is $12,000 and the rate of interest is 6% (simple interest), what
Elza [17]

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Answer:

  $12,720

Step-by-step explanation:

The amount is given by the formula ...

  A = P(1 +rt)

where P is the principal, invested at rate r for t years.

  A = $12,000(1 +0.06·1) = $12,720

The total amount after 1 year is $12,720.

7 0
2 years ago
A butcher is dividing a round of beef into 3 equal sized roasts. If each roast weighs 7.9 pounds, and there are 1.4 pounds of be
Gelneren [198K]
The answer is B hope it helps :)
7 0
3 years ago
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Find all solutions to the equation in the interval [0, 2īt).<br> 4) sin 2x = -sin x
Sonbull [250]

Answer:

x={0, 2pi/3, pi, 4pi/3}

Step-by-step explanation:

First, move sin x by adding sin x to both sides. sin 2x+ sin x = 0. Next using the double angle identity, sin 2x=2(sin x)(cos x), so 2(sin x)(cos x)+sinx=0. Factoring, sin x(2cos x +1)=0. Solving, sin x=0 and 2cos x +1 = 0, or cos x = -1/2.

sin x = 0. Using the unit circle, sin x=0 when x=0 and x=pi.

cosx=-1/2. Using the unit circle, cos x= -1/2 when x=2pi/3 and x=4pi/3.

8 0
3 years ago
Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

e) E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

f) E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

4 0
3 years ago
PLS HELP! Tell whether each of the following is a function or not. How do you know?
Nataly [62]

Answer: It is

Step-by-step explanation:

None of the lines will ever touch each other resulting in a function.

7 0
2 years ago
Read 2 more answers
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