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sashaice [31]
3 years ago
15

Experimental Probability is ___________ . a . our prediction b. data from our experiment

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0

Answer:

its B

Step-by-step explanation:

oksian1 [2.3K]3 years ago
7 0

Answer:

b. data from our experiment

Step-by-step explanation:

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PLEASE HELP WILL MARK BRAINLIEST IF CORRECT
aksik [14]

Answer:

I think 3

Step-by-step explanation:

i think 3

for real this time

3 0
3 years ago
Row counted a total of 40 white cars and yellow cars there were nine times as many white cars as yellow cars how many white cars
Tju [1.3M]
You multiply 40x9 and you should get 360
8 0
3 years ago
The current process has a mean of 2.50 and a std deviation of 0.05. A new process has been suggested by research. What sample si
Novay_Z [31]

Answer:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

n=(\frac{z_{\alpha/2} s}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.05)}{0.02})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)  

\sigma=0.05 represent the population standard deviation  

n represent the sample size (variable of interest)  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}  

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =0.02 and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} s}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.05)}{0.02})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

7 0
3 years ago
1/3 + 1/5 step by step
ella [17]

Answer:

8/15

Step-by-step explanation:

the denominators are different so you need to find the lowest common multiple which is 15

you times 3 by five so you have to change the 1 into 5

you times 5 by three so you have to change the other numerator to 3

so it becomes:

5/15 + 3/15= 8/15

8 0
3 years ago
Read 2 more answers
With the table below, find F(-87)
xz_007 [3.2K]

Answer:

right

Step-by-step explanation:

5 0
3 years ago
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