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e-lub [12.9K]
3 years ago
14

Calculate the pay for the following day of a

Mathematics
1 answer:
DedPeter [7]3 years ago
8 0

Answer:

Step-by-step explanation:

The person works 8.5 hours that day at a rate of $16/hr. 16 x 8.5 = $136

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Solve This equation and Show Work<br> 1/2d + 3/8 = -2d
Effectus [21]

½d + 3/8 = -2d

<span>-½d           -½d</span>

<span>3/8          = -2 ½d</span>

<span>/(-2 ½)      /(-2 ½)</span>

<span>3/20        = d </span>

5 0
3 years ago
HELP PLEASE Enter the equation of the circle with the given center and radius.
masha68 [24]

Answer:

(x + 2)² + (y + 9)² = 49

Step-by-step explanation:

Equation:

(x - h)² + (y - k)² = r²

(x - -2)² + (y - -9)² = 7²

(x + 2)² + (y + 9)² = 49

5 0
3 years ago
Expressions and Equations
Anna71 [15]

Answer:

A) 4x+8

B) 8x-16

C) 8x+12

D) 6x+6y+6z

Step-by-step explanation:

multiple the number outside of the parentheses by each number or letter inside the parentheses

8 0
3 years ago
Use any method to multiply (3a + 2b - c)(a - b + 2c).​
Alla [95]

Answer: 3a^{2}-ab + 5ac- 2b^{2} + 5bc-2c^{2}

Step-by-step explanation:

(3a + 2b − c) (a − b + 2c)  

Expand (3a + 2b − c) (a − b + 2c) by multiplying each  term in the first  expression by each  term in the second expression.

3a ⋅ a + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3 (a ⋅ a) + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 + 3 ⋅ −1ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 3 ⋅ 2ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b ⋅ b + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1 (b ⋅ b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b^2 + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2 ⋅ 2bc − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − 1 ⋅ −1cb − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + 1cb − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c ⋅ c

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2 (c ⋅ c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c^2

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − 3ab + 2ab + 6ac − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − ab + 6ac − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + 6ac − 1ac + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + 5ac + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + bc + 5ac − 2c^2

3a^2 − ab − 2b^2 + 5bc + 5ac − 2c^2

3a^2 − ab − 2b^2 + 5ac + 5bc − 2c^2

3a^2 − ab + 5ac − 2b^2 + 5bc − 2c^2

6 0
2 years ago
What's the algebraic expression for 5,9,13,17,21
Bad White [126]
1,5,9,13,17,21,25,29..., 4n+1
in general terms of an arithmetic sequence with the first term A0 and common differences d,
5 0
3 years ago
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