Answer:
An object at rest stays at rest as long as unbalanced forces act on it.
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
In physics, Sir Isaac Newton's First Law of Motion is known as Law of Inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
The inertia of a physical object such as a truck is greatly dependent or influenced by its mass; the higher the quantity of matter in a truck, the greater will be its tendency to continuously remain at rest.
Hence, the situation which is contrary to Newton’s first law of motion is that, an object at rest stays at rest as long as unbalanced forces act on it.
According to Newton’s first law of motion, an object at rest stays at rest as long as unbalanced forces do not act on it.
Answer:
Explanation:
Let 100 m/s be the velocity of projection.
So horizontal component
= 100 cos42
= 74.31 m /s
Vertical component = - 100 sin 42 . in upward direction
66.91 m/s
Net displacement = 2.1 downwards ( + ve )
Using s = ut + 1/2 gt²
2.1 = - 66.91 t + .5 x 9.8 x t²
4.9 t² - 66.91 t - 2.1 = 0
t = 13.685 s
Horizontal distance covered
= 13.685 x 74.31
= 1016.93 m
If angle of projction is 40°
So horizontal component
= 100 cos40
= 76.60 m /s
Vertical component = - 100 sin 42 . in upward direction
64.27 m/s
Net displacement = 2.1 downwards ( + ve )
Using s = ut + 1/2 gt²
2.1 = -76.60 t + .5 x 9.8 x t²
4.9 t² - 76.60 t - 2.1 = 0
t = 15.659 s
Horizontal distance covered
= 15.659 x 76.60
= 1199.49 m
So horizontal range is increased , if angle of projection is increased .
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
b
Explanation:
From the question we are told that
The amplitude is 
The period is 
The test weight is 
Generally the radial acceleration is mathematically represented as
at maximum angular acceleration
So
Now 
is the angular velocity which is mathematically represented as
Therefore
![a_{max} = [\frac{2 * \pi}{T} ]^2 * A](https://tex.z-dn.net/?f=a_%7Bmax%7D%20%3D%20%20%5B%5Cfrac%7B2%20%2A%20%20%5Cpi%7D%7BT%7D%20%5D%5E2%20%2A%20A)
substituting values
![a_{max} = [\frac{2 * 3.142}{17} ]^2 * 0.018](https://tex.z-dn.net/?f=a_%7Bmax%7D%20%3D%20%20%5B%5Cfrac%7B2%20%2A%20%203.142%7D%7B17%7D%20%5D%5E2%20%2A%200.018)
Generally this test weight is mathematically represented as
Where k is the spring constant
Therefore
substituting values
Answer:
4 m/s
Step-by-Step Explanation:
E = mgh and h = E/mg
So if you put your numbers in the formula : h = 4000J/500 * 10
you will get h = 4/5 meters
use this , If the elevator moves from top to the ground in a constasnt acceleration you will have all energy (4000 J) transformed into acceleration to speed up its motion.
(All potential energy will be turned into movement energy). As explained in this formula;
mgh = mv²/2 , solve out (v) from the equation
v = √2gh = √2·10·4/5 (digits are together- not related to the problem, just for clarification) = 4 m/s
Answer the velocity of the elevator is
4 m/s
This isn’t anything related to physics dude
