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avanturin [10]
3 years ago
14

Electric current is the flow of charged particles called blank .

Physics
2 answers:
uysha [10]3 years ago
7 0

The electric current is measured in coulombs per second.<u> A flow of one coulomb per second is called one ampere</u>

Alinara [238K]3 years ago
5 0

The electric current is the flow of electrons which are negatively charged particles.

<u>  Explanation:</u>

The flow of electrons in a circuit is called the electric current. It is measured with one coulomb of charge across the circuit in 1 second that is called an ampere. This ampere is the standard unit of electric current.

The flow of electrons across the circuit is achieved by the potential difference across the circuit. This potential difference is the difference of electrical voltage generated across the circuit in order to achieve flow of current.

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How long will a plane have to fly continuously with 900 miles per hour in order to cover the same distance as that from Earth to
hammer [34]

I'm not sure about the distance to the nearest star, but it's probably about        4 light-years (L-y).

1 L-y = 1.86 * 10E5 mi/sec * 3600 sec/hr * 24 hr/day * 365 day/yr

1 L-y = 5.9 *10E12 mi   and 4 L-y = 2.3 *10E13 mi    distance to star

2.3 * 10E13 mi / 900 mi/hr = 2.6 * 10E10 hr       hours to star

2.6 * 10E10 hr / (24 hr/day) = 1.1 * 10E9 day     days to star

1.1 * 10E9 day / 365 day/yr = 3 * 10E6 yr = 3 million years to star

4 0
3 years ago
Why does water’s high specific heat make it a good coolant for car radiators?.
Alexeev081 [22]

Answer:

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Explanation:

i hope this answer your question if it s wrong please let know

7 0
2 years ago
Read 2 more answers
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5 0
3 years ago
A 2-kg bowling ball is 1 meter off the ground on a post when it falls. Just before it reaches the ground, it is traveling 4.4 m/
noname [10]
With the given information you can find the initial and final mechanical energies. Then we can verify the conservation of it.

1) Initially the ball is at rest 1 m over the ground, then its mechanical energy is only potential energy = m*g*h = 2kg * 9.8m/s^2 * 1m = 19.6 joule

2) When the ball is above to hit the ground, its mechanical energy is only kinetic energy = [1/2]m*v^2 = [1/2]2kg*(4.4m/s)^2 = 19.4 joule 

Those results, taken into account that the measures have some errors (for example the exact velocity of the ball when it reaches de floor is quite difficult to measure) confirm the conservation of the energy.

Then, the answer is the option B. The mechanical energy is conserved
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3 years ago
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Answer:

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