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Mkey [24]
3 years ago
10

A certain freely falling object, released from rest, requires 1.60 s to travel the last 29.0 m before it hits the ground. (a) Fi

nd the velocity of the object when it is 29.0 m above the ground. (Indicate the direction with the sign of your answer. Let the positive direction be upward.)
Physics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

-10.277 m/s

Explanation:

t = Time taken = 1.6 s

s = Distance travelled = 29 m

u = Initial velocity

a = Acceleration due to gravity = 9.81 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow -29=u\times 1.6-\frac{1}{2}9.81\times 1.6^2\\\Rightarrow -29+\frac{1}{2}9.81\times 1.6^2=u1.6\\\Rightarrow -16.4432=u1.6\\\Rightarro u=\frac{-16.4432}{1.6}=-10.277\ m/s

∴ Velocity of the object when it is 29.0 m above the ground is -10.277 m/s

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Answer:

The total displacement from the starting point is 1.5 m.

Explanation:

You need to sum and substract, depending on the movement (to the right, sum; to the left, substract).

First, it moves 4.3 m right and return 1.1 m. So the new distance from the starting point is 3.2 m.

Second, it moves 6.3 m right, so the new distance is 9.5 m.

Finally it moves 8 m to the left, so 9.5 m - 8 m= 1.5 m.

Summarizing, at the end the squirrel is 1.5 m from its starting point.

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A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q
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Answer:

The magnitude of the electrostatic force is 120.85 N

Explanation:

We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges q_1 and q_2 separated by a distance d, the magnitude of the electrostatic force F between them is:

F = k \frac{|q_1q_2|}{d^2}

where k is Coulomb's constant.

Taking the values:

d = 4.6 \ 10^{-15} m

q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}

and knowing the value of the Coulomb's constant:

k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}

Taking all this in consideration:

F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}

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8 0
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Answer:

PlROCA

Explanation:

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3 years ago
A car is traveling at a speed of 10m/s. A 0.5kg clump of mudis
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Answer:B

Explanation:

Given

speed of car v=10 m/s

mass of clump m=0.5 kg

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Since the tire is rotating about axle so a centripetal force is acting constantly on each particle towards the center of tire.

Centripetal force is given by

F_c=\frac{mv^2}{r}

where m=mass\ of\ element

v=speed

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F_c=\frac{0.5\times 10^2}{0.2}

F_c=250\ N (inward)

           

3 0
4 years ago
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Answer:

Correct Answer is positive force → balanced force → negative force

Explanation:

When Diego gives a big lift to the piano with the help of pulley system that time, initially piano moves upward so positive force acts on it.

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4 years ago
Read 2 more answers
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