1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ch4aika [34]
4 years ago
10

A squirrel is trying to locate some nuts he buried for the winter. He moves 4.3 m to the right of a stone and dogs unsuccessfull

y. Then he moves 1.1 m to the left of his hole, changes his mind, and moves 6.3 m to the right of that position and digs a second hole. No luck. Then he moves 8.0 m to the left and digs again. He finds a nut at last. What is the squirrel's total displacement from his starting point
Physics
1 answer:
krek1111 [17]4 years ago
8 0

Answer:

The total displacement from the starting point is 1.5 m.

Explanation:

You need to sum and substract, depending on the movement (to the right, sum; to the left, substract).

First, it moves 4.3 m right and return 1.1 m. So the new distance from the starting point is 3.2 m.

Second, it moves 6.3 m right, so the new distance is 9.5 m.

Finally it moves 8 m to the left, so 9.5 m - 8 m= 1.5 m.

Summarizing, at the end the squirrel is 1.5 m from its starting point.

You might be interested in
I dont understand how to find the blanks​
Amiraneli [1.4K]

The forces are:

F_{grav} = 98,000 N, down

F_{net} = 80,000 N, down

F_{air}=18,000 N, up

Explanation:

We start by finding the force of gravity on the elephant, F_{grav}, which is given by

F_{grav}=mg (downward)

where

m = 10,000 kg is the mass of the elephant

g=9.8 m/s^2 is the acceleration of gravity

Substituting,

F_{grav}=(10,000)(9.8)=98,000 N

Now we know that the net acceleration of the elephant is

a_{net}=8.0 m/s^2 downward

We can now use Newton's second law:

F_{net}=ma_{net}

where F_{net} is the net force on the elephant. Substituting, we find

F_{net}=(10,000)(8.0)=80,000 N

and it also acts downward, since it has the same direction as the acceleration.

Finally, we can write the net force on the elephant as

F_{net}=F_{grav}-F_{air}

where the force of gravity acts downward, while the air resistance (F_{air} acts upward. The net force also acts downward, so it has the same sign of gravity.

Substituting:

F_{net}=80,000 N\\F_{grav}=98,000 N

And solving, we find the air resistance:

F_{air}=F_{grav}-F_{net}=98,000-80,000 = 18,000 N (upward)

Learn more about forces and Newton laws of motion:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

4 0
4 years ago
A tourist stands at the top of the Grand Canyon, holding a rock, overlooking the valley below. Find the final velocity and displ
Anestetic [448]

Answer:

a. -39.2 m/s; -78.4 m

b. -31.2 m/s; -46.4 m

c. -47.2 m/s; -110.4 m

Explanation:

<h2>Part (a)</h2>

We are given/can infer these variables:

  • t = 4.0 s
  • a = -9.8 m/s²
  • v_0 = 0 m/s

We want to find the displacement and the final velocity of the rock.

  • Δx = ?
  • v = ?

We can use this equation to find the final velocity:

  • v = v_0 + at

Plug in the known variables into this equation.

  • v = 0 + (-9.8)(4.0)
  • v = -9.8 * 4.0
  • v = -39.2 m/s

The final velocity of the rock is -39.2 m/s.

Now we can use this equation to find the displacement of the rock:

  • Δx = v_0 t + 1/2at²

Plug in the known variables into this equation.

  • Δx = 0 * 4.0 + 1/2(-9.8)(4.0)²
  • Δx = 1/2(-9.8)(4.0)²
  • Δx = -4.9 * 16
  • Δx = -78.4 m

The displacement of the rock is -78.4 m.

<h2>Part (b)</h2>

We are given/can infer these variables:

  • v_0 = 8.0 m/s
  • a = -9.8 m/s²
  • t = 4.0 s

We can use this equation to find the final velocity:

  • v = v_0 + at

Plug in the known variables into this equation.

  • v = 8.0 + (-9.8)(4.0)
  • v = 8.0 + -39.2
  • v = -31.2 m/s

The final velocity of the rock is -31.2 m/s.

We can use this equation to find the displacement:

  • Δx = v_0 t + 1/2at²

Plug in known variables:

  • Δx = 8.0(4.0) + 1/2(-9.8)(4.0)²
  • Δx = 32 - 4.9(16)
  • Δx = -46.4 m

The displacement of the rock is -46.4 m.

<h2>Part (c)</h2>

We are given/can infer these variables:

  • v_0 = -8.0 m/s
  • a = -9.8 m/s²
  • t = 4.0 s

We can use this equation to find the final velocity:

  • v = v_0 + at

Plug in the known variables into this equation.

  • v = -8.0 + (-9.8)(4.0)
  • v = -8.0 - 39.2
  • v = -47.2 m/s

The final velocity of the rock is -47.2 m/s.

We can use this equation to find the displacement:

  • Δx = v_0 t + 1/2at²

Plug in known variables:

  • Δx = -8.0(4.0) + 1/2(-9.8)(4.0)²
  • Δx = -32 - 4.9(16)
  • Δx = -110.4 m

The displacement of the rock is -110.4 m.

8 0
4 years ago
How do you calculate displacement on a graph
guapka [62]

Explanation:

On a position vs time graph (x vs t), displacement is the difference in positions (Δx = x₂ − x₁).

On a velocity vs time graph (v vs t), displacement is the area under the graph (Δx = ∫ v dt).

6 0
3 years ago
A 240 m long segment of wire is hanging between 2 transmission lines. What is the total magnetic force only (ignore gravitationa
Delvig [45]

Answer:

<em>7.2 N</em>

Explanation:

length of wire L  = 240 m

current I = 500 A

field strength B = 3 x 10^-5 T

magnetic force on a current carrying conductor F is given as

F = BILsin∅

The wires are perpendicular with field therefore sin∅ = sin 90° = 1

therefore,

F = BIL = 3 x 10^-5 X 500 X 240 = 3.6 N

<em>If the wire exists between this two transmission lines, then total magnetic force on the wire = 2 x 3.6 = 7.2 N</em>

7 0
3 years ago
A cyclist moving with a constant velocity of 6.0 m/s forward passes a car that is just starting. If the car has a constant accel
sergiy2304 [10]

After 6 seconds, the car will surpass the cyclist.

<h3><u>Explanation:</u></h3>

The speed of the cyclist = 6 m/s.

Let after time t sec, the car will overtake the cyclist.

So, distance covered by the cyclist in t sec = 6t m

Initial velocity of the car is 0 m/s, because the car is just starting.

Acceleration of the car =2 m/s^2.

Final velocity of the car =6 m/s.

So to cover the distance 6t, the time required by the car = \frac{1}{2} \times a \times t^2 = \frac{1}{2} \times 2 \times t^2

6t = \frac{1}{2} \times 2 \times t^2\\6t = t^2

t =6 sec

So, after 6 seconds, the car will surpass the cycle.  

6 0
3 years ago
Other questions:
  • The man fire a 50-g arrow that moves at an unknown speed. It hits and embeds in a 350-g block that slides on an air track. At th
    10·1 answer
  • HELP ASAP!!!
    15·2 answers
  • A baseball pitcher throws a ball at 97.0 mi/h in the horizontal direction. How far does the ball fall vertically by the time it
    9·1 answer
  • The force between two moving objects that are touching
    8·2 answers
  • Example of competition on North Island<br><br> Help me plz 10 points
    12·1 answer
  • The graph below was created from the motion of a cart on a ramp. Use the graph to answer the question that follows.
    6·1 answer
  • A car starts at the top of a hill with 200 J of energy, and rolls down a frictionless surface. The isolated system consists of t
    8·1 answer
  • According to Freud, a person’s current perceptions and thoughts would be located at the __________ level. A. conscious B. noncon
    7·1 answer
  • Can you make sound you can see?​
    8·1 answer
  • Water waves that you might see at the beach move in circular or elliptical paths. What type of mechanical waves are water waves?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!