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tatiyna
3 years ago
7

Professional research telescopes should be large enough to gather sufficient radiation from space. Which of these statements bes

t explains why a reflecting telescope is best used as a professional research telescope?
Question 5 options:

Mirrors of reflecting telescopes gather harmful radiations from space.

Bigger lenses are easier to manufacture and they produce less distortion.

The series of mirrors and lenses help to reduce distortion of images.

Reflecting telescopes reflect away more radiation and distort images.
Physics
2 answers:
Llana [10]3 years ago
6 0

Answer:

Bigger lenses are easier to manufacture and they produce less distortion.

Explanation:

A reflecting telescope is best used as a professional research telescope because " Bigger lenses are easier to manufacture and they produce less distortion."

This is evident in the fact that the mirror of a reflecting telescope is simpler and inexpensive to be manufactured.

Also reflecting telescope is known not to support chromatic distortion, which often is a byproduct of dispersion.

MArishka [77]3 years ago
6 0

Answer:

Bigger lenses are easier to manufacture and they produce less distortion

Explanation:

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4 years ago
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Calculate, for the judge, how fast you were going in miles per hour when you ran the red light because it appeared Doppler-shift
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Answer:

The doppler effect equation is:

f' = \frac{v +v0}{v - vs}*f

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f = v/λ

and v is the speed of light, then:

f = c/λ

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f' is the observed frequency, in this case, is equal to f = (3*10^17nm/s)/550 nm

f is the real frequency, in this case, is (3*10^17nm/s)/650 nm

vs is the speed of the source, in this case, the source is not moving, then vs = 0 m/s.

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Replacing those quantities in the equation, we get:

(3*10^17nm/s)/550 = (3*10^8 m/s + v0)/(3*10^8 m/s)*(3*10^17nm/s)/650 nm

(650nm)/(550nm) = (3*10^8 m/s + v0)/(3*10^8 m/s)

1.182*(3*10^8 m/s) = (3*10^8 m/s + v0)

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So your speed was 54,600,000 m/s, which is a lot.

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