Let,
the numbers be "x" and "y"
According to the question,
x = 4y ......................................................equation (1)
![\frac{1}{x} + \frac{1}{y}= \frac{45}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%7D%20%2B%20%5Cfrac%7B1%7D%7By%7D%3D%20%5Cfrac%7B45%7D%7B4%7D%20%20)
...................................equation (2)
Taking equation (2)
![\frac{1}{x} + \frac{1}{y}= \frac{45}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%7D%20%2B%20%5Cfrac%7B1%7D%7By%7D%3D%20%5Cfrac%7B45%7D%7B4%7D)
Substituting the value of "x" from equation (1), we get,
![\frac{1}{(4y)} + \frac{1}{y}= \frac{45}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%284y%29%7D%20%2B%20%5Cfrac%7B1%7D%7By%7D%3D%20%5Cfrac%7B45%7D%7B4%7D)
![\frac{1}{4y} + \frac{1}{y}* \frac{4}{4} = \frac{45}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4y%7D%20%2B%20%5Cfrac%7B1%7D%7By%7D%2A%20%5Cfrac%7B4%7D%7B4%7D%20%3D%20%5Cfrac%7B45%7D%7B4%7D)
![\frac{1}{4y} + \frac{4}{4y}= \frac{45}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4y%7D%20%2B%20%5Cfrac%7B4%7D%7B4y%7D%3D%20%5Cfrac%7B45%7D%7B4%7D)
![\frac{1+4}{4y} = \frac{45}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%2B4%7D%7B4y%7D%20%3D%20%5Cfrac%7B45%7D%7B4%7D)
![\frac{5}{4y} = \frac{45}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B4y%7D%20%3D%20%5Cfrac%7B45%7D%7B4%7D)
Cross multiplying, we get,
![5*4 = 45*4y](https://tex.z-dn.net/?f=5%2A4%20%3D%2045%2A4y)
![20 = 180y](https://tex.z-dn.net/?f=20%20%3D%20180y)
<u />
![\frac{20}{180} = y](https://tex.z-dn.net/?f=%20%5Cfrac%7B20%7D%7B180%7D%20%20%3D%20y)
![\frac{1}{9} = y](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B9%7D%20%20%3D%20y)
![y = \frac{1}{9}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B9%7D)
Now,
Taking equation (1)
x = 4y
Substituting the value of "y", we get
![x = 4( \frac{1}{9} )](https://tex.z-dn.net/?f=x%20%3D%204%28%20%5Cfrac%7B1%7D%7B9%7D%20%29)
So, the numbers are
and
Add up all of your X’s!! then Try and add up all of the degrees I think. Check me if i’m wrong !
Answer:
The biggest - the smallest
612-120=492
Answer:
1000 is the best answer yet