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const2013 [10]
3 years ago
5

What is 1/2 to 1/4 equals

Mathematics
1 answer:
sergey [27]3 years ago
4 0

Do you mean 1/2 of 1/4 if so it’s just timsing the numerator by the numerator and the denominator by the denominator. So, 1 x 1 = 1 and 2 x 4 = 8

Therefore it’s 1/8!

If you didn’t understand I’ll gladly elaborate!

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One positive integer is 6 less than another. The
nlexa [21]

Answer:

11, 5

Step-by-step explanation:

x=y-6

xy=55

Put x as y-6 in the second equation.

(y-6)y=55

y^2-6y=55

y^2-6y-55=0

Factor.

\left(y+5\right)\left(y-11\right)=0

\left(y+5\right)=0

y=-5

It has to be a positive integer.

y-11=0

y=11

Substitute y as 11.

x=y-6

x=11-6

x=5

6 0
3 years ago
Read 2 more answers
If the points (4,2) (6,3) and (8,4) are on the graph of f, give three points on the graph of f^-1
Stels [109]

let's recall that an inverse function has the same pair of coordinates as the original function, but backwards, or namely the inverse's range is the original's domain.

\bf \stackrel{f(x)}{\begin{array}{|cc|ll} \cline{1-2} 4&2\\ 6&3\\ 8&4\\ \cline{1-2} \end{array}}\qquad \qquad \stackrel{f^{-1}(x)}{\begin{array}{|cc|ll} \cline{1-2} 2&4\\ 3&6\\ 4&8\\ \cline{1-2} \end{array}}

8 0
3 years ago
PLEASE WILL SOMEONE HELP ME? i WILL GIVE BRAINLIEST!!!
Fed [463]

B ∪ (C' ∩ A)

Starting from the inside, C' ∩ A is the intersection of not C, which is everything except the circle C, and A.  That's the part I shaded in bright blue.

That's unioned with B, which is just all of the circle B.  I shaded the parts of B that I didn't already shade with a grey-blue.

These should all be the same shade; I just made them slightly different for explanation.

4 0
3 years ago
Simplify the midpoint of QS.
oee [108]

Answer:

[(a + b), c]

Step-by-step explanation:

Midpoint of a segment with extreme ends represented by ordered pairs (x_1,y_1) and (x_2,y_2),

Midpoint = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

It is given that extreme ends of the segment QS are Q(2b, 2c) and S(2a, 0)

Coordinates of the midpoint of QS will be,

= (\frac{2a+2b}{2},\frac{2c+0}{2} )

= [(a + b), c]

Therefore, ordered pair representing the midpoint of QS will be [(a + b), c].

8 0
3 years ago
I really need help please!
Evgen [1.6K]
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