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2 years ago

How do you stand up straight to measure your height?

1 answer:

8 0

Look up plant your feet on the ground stretch your back and put your hand on your head mark your hand with a pencil on the wall just measure the ground to the mark you made

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A stadium has central rectangular area 125m long by 80 m wide there are two semicircular ends.running tracks goes all way round

olga_2 [115]

) Using formula for cicumference.

Circumference = Pi * diameter

Circumference = Pi * 80m

Circumference = 251.2m.

Total inside length of the curved ends.

2)Total distance round inside of track =

2(125) + 251.2m

= 250 + 251.2

= 501.2m

3) Area of circular ends =

Pi*r^2

= Pi*40^2

= 5024m^2

Area of central area (rectangle)

length * width

125m * 80m

= 10,000m^2

Total area inside track =

5,024m^2 + 10,000m^2

= 15,024m^2

Hope this helps.

:-)

7 0

3 years ago

What is the length of a diagonal of a cube with a side length of 3 cm?

hodyreva [135]

The answer to that question is 27 cm

4 0

2 years ago

Jason states that Triangle A B C is congruent to triangle R S T. Kelley states that Triangle A B C is congruent to triangle T S

Brilliant_brown [7]

Answer:

The correct option is;

Jason's statement is correct. RST is the same orientation, shape, and size as ABC

Step-by-step explanation:

Here we have

ABC = (2, 1), (3, 3), (4, 1)

RST = (-4, -2), (-3, 0), (-2, -2)

Therefore the length of the sides are as follows

AB = $\sqrt{(2-3)^2+(1-3)^2} = \sqrt{5}$

AC = $\sqrt{(2-4)^2+(1-1)^2} =2$

BC = $\sqrt{(3-4)^2+(3-1)^2} = \sqrt{5}$

For triangle SRT we have

RS = $\sqrt{(-4-(-3))^2+(-2-0)^2} = \sqrt{5}$

RT = $\sqrt{(-4-(-2))^2+(-2-(-2))^2} = 2$

ST = $\sqrt{(-3-(-2))^2+(0-(-2))^2} = \sqrt{5}$

Therefore their dimensions are equal

However the side with length 2 occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST

That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.

4 0

3 years ago

Read 2 more answers

Find the average rate of change of f(x) = 4x² – 3 from 3 to 9.

Lina20 [59]

Answer:

Step-by-step explanation:

Given:

$f(x) = 4x^2 - 3$

Required:

Average range of change from 3 to 9

SOLUTION:

Step 1:

Find f(3) and f(9):

To find f(3), replace x with 3 in the given function

$f(3) = 4(3)^2 - 3$

$f(3) = 4(9) - 3$

$f(3) = 36 - 3$

$f(3) = 33$

To find f(9), replace x with 9 in the given function

$f(9) = 4(9)^2 - 3$

$f(9) = 4(81) - 3$

$f(9) = 324 - 3$

$f(9) = 321$

Average rate of change = $\frac{f(b) - f(a)}{b - a}$

Where,

$a = 3, f(a) = 33$

$b = 9, f(b) = 321$

Plug in the values into the formula for average rate of change.

$= \frac{321 - 33}{9 - 3}$

$= \frac{288}{6}$

$= 44$

Average rate of change = 44

3 0

3 years ago

Match the sentences below to the correct vocabulary word.

Veseljchak [2.6K]

Answer:

2134

Step-by-step explanation:

beacuse that is the wright answer

6 0

3 years ago

Read 2 more answers

How do you stand up straight to measure your height?​

How do you stand up straight to measure your height?