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aleksley [76]
3 years ago
14

Apart from ultrasound what is the other type of wave that can be used to look inside the human body

Physics
2 answers:
ira [324]3 years ago
5 0

Answer:

X rays

Explanation:

We use x-rays to view bones

mart [117]3 years ago
5 0
X-rays can be used to look inside the human body
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An object with a resistance of 28 Ω has 76 V applied to it. How much electric current is going through this object? Answer in un
12345 [234]

Answer : The electric current of a circuit is, 2.8 A.

Explanation :

Using Ohm's law :

V=I\times R

Or,

I=\frac{V}{R}

where,

R = resistance of a circuit = 28 Ω

V = voltage of circuit = 76 volts = 76 V

I = current flowing in a circuit = ?

Now put all the given values in the above formula, we get :

I=\frac{V}{R}

I=\frac{76V}{28\Omega }

I=2.8A

Therefore, the electric current of a circuit is, 2.8 A

5 0
3 years ago
What happens during constructive interference?
Fofino [41]
A

  ~~~hope this helps~~~
~~have a beautiful day~~
            ~davatar~
3 0
3 years ago
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How do prices help determine for whom goods will be produced in a market economy
yKpoI14uk [10]
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7 0
4 years ago
If two light waves are coherent a) their amplitudes are the same their phase difference is constant their frequencies are the sa
Aleonysh [2.5K]

Answer:

a) their amplitudes are the same their phase difference is constant their frequencies are the same

Explanation:

Coherent waves are the waves that have constant phase difference, equal frequency, amplitude and waveform.

Frequency denotes the number of cycles a wave completes in one second.

Amplitude is the maximum height that the wave reaches.

Waveform is the two dimensional representation of a wave in graphical form.

3 0
3 years ago
A sphere has surface area 1.25 m2, emissivity 1.0, and temperature 100.0°C. What is the rate at which it radiates heat into empt
Yuri [45]
The total power emitted by an object via radiation is:
P=A\epsilon \sigma T^4
where:
A is the surface of the object (in our problem, A=1.25 m^2
\epsilon is the emissivity of the object (in our problem, \epsilon=1)
\sigma = 5.67 \cdot 10^{-8} W/(m^2 K^4) is the Stefan-Boltzmann constant
T is the absolute temperature of the object, which in our case is T=100^{\circ} C=373 K

Substituting these values, we find the power emitted by radiation:
P=(1.25 m^2)(1.0)(5.67 \cdot 10^{-8}W/(m^2K^4)})(373 K)^4=1371 W = 1.4 kW
So, the correct answer is D.
6 0
3 years ago
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