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3 years ago

What is nuclear fission?

2 answers:

tatiyna3 years ago

7 0

Nuclear fission is: A nuclear reaction in which a heavy nucleus splits spontaneously or on impact with another particle, with the release of energy.

Hope I helped!

- Debbie

Allushta [10]3 years ago

7 0

An chain reaction of atoms splitting into smaller nuclei

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The formula shown below is used to calculate the energy released when a specific quantity of fuel is burned. Calculate the energ

olya-2409 [2.1K]

Answer: 8400 J

Explanation:

The formula referenced in the question is:

$Q=m. c. \Delta T$

Where:

$Q$ is the thermal energy

$m=100g \frac{1 kg}{1000 g}=0.1 kg$ is the mass of the water sample

$c=4200 \frac{J}{kg\°C}$ is the specific heat capacity of water

$\Delta T=20\°C$ is the variation in temperature

Solving:

$Q=(0.1 kg)(4200 \frac{J}{kg\°C})(20\°C)$

$Q=8400 J$ This is the thermal energy released

8 0

3 years ago

If a ball is dropped into a very viscous liquid it will

Dafna1 [17]

It will go to the bottom of the liquid very slowly. Good Luck!

7 0

3 years ago

A 10-kg disk-shaped flywheel of radius 9.0 cm rotates with a rotational speed of 320 rad/s. Part A Determine the rotational mome

Leya [2.2K]

Answer:

(A). The rotational momentum of the flywheel is 12.96 kg m²/s.

(B). The rotational speed of sphere is 400 rad/s.

Explanation:

Given that,

Mass of disk = 10 kg

Radius = 9.0 cm

Rotational speed = 320 m/s

(A). We need to calculate the rotational momentum of the flywheel.

Using formula of momentum

$L=I\omega$

$L=\dfrac{1}{2}mr^2\omega$

Put the value into the formula

$L=\dfrac{1}{2}\times10\times(9.0\times10^{-2})^2\times320$

$L=12.96\ kg m^2/s$

(B). Rotation momentum of sphere is same rotational momentum of the flywheel

We need to calculate the magnitude of the rotational speed of sphere

Using formula of rotational momentum

$L_{sphere}=L_{flywheel}$

$I\omega_{sphere}=I\omega_{flywheel}$

$\omega_{sphere}=\dfrac{I\omega_{flywheel}}{I_{sphere}}$

$\omega_{sphere}=\dfrac{I\omega_{flywheel}}{\dfrac{2}{5}mr^2}$

Put the value into the formula

$\omega_{sphere}=\dfrac{12.96}{\dfrac{2}{5}\times10\times(9.0\times10^{-2})^2}$

$\omega_{sphere}=400\ rad/s$

Hence, (A). The rotational momentum of the flywheel is 12.96 kg m²/s.

(B). The rotational speed of sphere is 400 rad/s.

4 0

3 years ago

When growing tomatoes with little sunlight, will using a mirror to reflect the sunlight give the same result as direct sunlight?

telo118 [61]

Answer:

No, it is not d true light

Explanation:

fruits generally plants need a direct sunlight

4 0

4 years ago

The storage coefficient of a confined aquifer is 6.8x10-4 determined by a pumping test. The thickness of the aquifer is 50 m and

Ivanshal [37]

Answer

given,

storage coefficient, S = 6.8 x 10⁻⁴

thickness of aquifer, t = 50 m

porosity of the aquifer, n = 25 % = 0.25

Density of the water, γ = 9810 N/m³

Compressibilty of water,β = 4.673 x 10⁻¹⁰ m²/N

We know,

S = γ t(nβ + α)

where, α is the compressibility of the aquifer

6.8 x 10⁻⁴ =9810 x 50 x (0.25 x 4.673 x 10⁻¹⁰+ α)

α = 1.269 x 10⁻⁹ m²/N

Expansability of water

= n t β γ

= 0.25 x 50 x 4.673 x 10⁻¹⁰ x 9810

= 5.73 x 10⁻⁵

7 0

3 years ago