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Dmitriy789 [7]
3 years ago
7

An object with a resistance of 28 Ω has 76 V applied to it. How much electric current is going through this object? Answer in un

its of amps.
Physics
1 answer:
12345 [234]3 years ago
5 0

Answer : The electric current of a circuit is, 2.8 A.

Explanation :

Using Ohm's law :

V=I\times R

Or,

I=\frac{V}{R}

where,

R = resistance of a circuit = 28 Ω

V = voltage of circuit = 76 volts = 76 V

I = current flowing in a circuit = ?

Now put all the given values in the above formula, we get :

I=\frac{V}{R}

I=\frac{76V}{28\Omega }

I=2.8A

Therefore, the electric current of a circuit is, 2.8 A

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Describe what happens to chromosomes before mitosis.
Brums [2.3K]

Explanation:

Before mitosis, the chromosomes are copied. They then coil up, and each chromosome looks like a letter X in the nucleus of the cell. The chromosomes now consist of two sister chromatids. Mitosis separates these chromatids, so that each new cell has a copy of every chromosome

6 0
3 years ago
How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 25.0 cm in diameter to p
katrin [286]

Answer:

Required charge q=2.6\times 10^{9}C.

n=1.622\times 10^{10}\ electrons

Explanation:

Given:

Diameter of the isolated plastic sphere = 25.0 cm

Magnitude of the Electric field = 1500 N/C

now

Electric field (E) is given as:

E =\frac{kq}{r^2}

where,

k = coulomb's constant = 9 × 10⁹ N

q = required charge

r = distance of the point from the charge where electric field is being measured

The value of r at the just outside of the sphere = \frac{25.0}{2}=12.5cm=0.125m

thus, according to the given data

1500N/C=\frac{9\times 10^{9}N\times q}{(0.125m)^2}

or

q=\frac{0.125^2\times 1500}{9\times 10^{9}}

or

Required charge q=2.6\times 10^{9}C.

Now,

the number of electrons (n) required will be

n=\frac{required\ charge}{charge\ of\ electron}

or

n=\frac{2.6\times 10^{-9}}{1.602\times 10^{-19}}

or

n=1.622\times 10^{10}\ electrons

6 0
4 years ago
The total pressure inside a 1.43 L cylinder at 28C is 1.03 atm. If the temperatures drops to -35C, and the volume remains the sa
Art [367]

Answer:

0.81452 atm

Explanation:

P_1 = Initial pressure = 1.43 L

V_1=V_2 = Volume

T_1 = Initial temperature = (28+273.15)  K

T_2 = Final temperature = (-35+273.15) K

P_2 = Final pressure

From the ideal gas law we have

\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow P_2=\dfrac{P_1V_1T_2}{T_2V_2}\\\Rightarrow P_2=\dfrac{1.03\times 1.43\times (273.15-35)}{(273.15+28)1.43}\\\Rightarrow P_2=0.81452\ atm

The pressure in the cylinder is 0.81452 atm

8 0
3 years ago
Johanna makes the table below to organize her notes about centripetal forces.
umka21 [38]

Gravity

Explanation:

Johanna's table:

       Circular motion                        Centripetal force

       space station in orbit                         X

        a child in a swing

         a ball on a string

The type of centripetal force at work in a space station in orbit is the force of gravity.

The force of gravity is constantly pulling and attractive all objects and bodies to its center.

This force is directed towards the center of the orbit of the earth and it is a centripetal force

  • Gravity attracts any object that has mass.
  • The mass of the satellite and the earth keeps it in orbit and prevents it from moving out of orbit.
  • The more the mass the more the gravitational attraction.

learn more

Universal Gravitation brainly.com/question/1724648

#learnwithBrainly

3 0
3 years ago
Read 2 more answers
Calculate the weight of an object that has a mass of 100 kg on earth
finlep [7]

Answer:

W = 980 N

Explanation:

Weight = Mass x Gravity

Weight = (100kg) x (9.8\frac{m}{s^2})

Weight = 980 N

7 0
3 years ago
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