Two bodies of masses M and m(M>m) are allowed to fall from the same height. If
1 answer:
- Two bodies of masses M and m (M>m) are allowed to fall from the same height . If the air resistance for each be the same then both the bodies will reach the earth simultaneously .
- For same air resistance, acceleration of both the bodies will be same .
[A] If both assertion and reason are true and reason is the correct explanation of assertion .
[B] If both assertion and reason are true but reason is not the correct explanation of assertion .
[C] If assertion is true but reason is false
[D] If both assertion and reason are false
✍️ The force acting on the body of mass M are [its weight] ‘<u>Mg</u>’
- Mg are acting vertically downwards
- And air resistance F acting vertically upward .
Hence,
⚡ Now, M > m therefore, the body with larger mass will have greater acceleration and it will reach the ground first .
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Answer:
a) m = 69.0 kg
b) release some gas in the opposite direction to the astronaut's movement
Explanation:
a) Let's use Newton's second law
F = m a
m = F / a
m = 60.0 / 0.870
m = 69.0 kg
b) when we exert a force on the astronaut it acquires a momentum po, as the astronaut system plus spacecraft is isolated, the momentum is conserved
p₀ = p_f
m v = M v '
v ’=
so we see that the ship is moving backwards, but since the mass of the ship is much greater than the mass of the astronaut, the speed of the ship is very small.
One method to avoid this effect is to release some gas in the opposite direction to the astronaut's movement so that the initial momentum of the astronaut plus the gas is zero and therefore no movement is created in the spacecraft.