Two bodies of masses M and m(M>m) are allowed to fall from the same height. If
1 answer:
- Two bodies of masses M and m (M>m) are allowed to fall from the same height . If the air resistance for each be the same then both the bodies will reach the earth simultaneously .
- For same air resistance, acceleration of both the bodies will be same .
[A] If both assertion and reason are true and reason is the correct explanation of assertion .
[B] If both assertion and reason are true but reason is not the correct explanation of assertion .
[C] If assertion is true but reason is false
[D] If both assertion and reason are false
✍️ The force acting on the body of mass M are [its weight] ‘<u>Mg</u>’
- Mg are acting vertically downwards
- And air resistance F acting vertically upward .
Hence,
⚡ Now, M > m therefore, the body with larger mass will have greater acceleration and it will reach the ground first .
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Answer:
a = 3.125 [m/s^2]
Explanation:
In order to solve this problem, we must use the following equation of kinematics. But first, we have to convert the speed of 90 [km/h] to meters per second.
where:
Vf = final velocity = 25 [m/s]
Vi = initial velocity = 0
a = acceleration [m/s^2]
t = time = 8 [s]
The initial speed is zero as the bus starts to koverse from rest. The positive sign of the equation means that the bus increases its speed.
25 = 0 + a*8
a = 3.125 [m/s^2]