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s344n2d4d5 [400]
2 years ago
9

A painter needs to cover a triangular region 60 meters by 68 meters by 72 meters. a can of can cover 70 square meters.. how many

cans will be needed??,
Mathematics
1 answer:
Inessa05 [86]2 years ago
3 0

Answer:

28 cans is the correct answer

Step-by-step explanation:

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25

Step-by-step explanation:

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Figure 1 is similar to figure 2
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Yes I think that is correct
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Please help me with this , it would mean alot​
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Answer:

Step-by-step explanation:

21-26. a = v - u / t

=> a = 47 - 19 / 5

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=> v = 150 / 40

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4 0
2 years ago
Sphere A is similar to Sphere B. The scale factor of the lengths of the radii of Sphere A to Sphere B is 1 to 4. Sphere A has th
AleksAgata [21]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{\textit{sphere A}}{\textit{sphere B}}\qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}\qquad \qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}=\stackrel{\stackrel{volumes'}{ratio}}{\cfrac{\sqrt[3]{288}}{\sqrt[3]{v}}}\implies \cfrac{1}{4}=\sqrt[3]{\cfrac{288}{v}}\implies \left( \cfrac{1}{4} \right)^3=\cfrac{288}{v} \\\\\\ \cfrac{1^3}{4^3}=\cfrac{288}{v}\implies \cfrac{1}{64}=\cfrac{288}{v}\implies v=18432

3 0
3 years ago
Hi!!!! Can someone please help me answer this math question??
GalinKa [24]
The shortcut is the hypotenuse of a right triangle with legs 6 and 8, so 6²+8²=c²

36+64=c
100=c²
c=10.
so he traveled 6+8+10=24km
6 0
3 years ago
Read 2 more answers
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