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puteri [66]
3 years ago
11

We play a game where there are 50 coins in a row, we take turns taking between 1 and 5 coins however many you like. whoever take

s the last coin keeps them all. how can i win everytime and does it matter if i go first
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0
The strategy for winning every time appears to be to ensure that the remaining number of coins is a multiple of 6. Then the first player can ensure a win by taking 2 coins to make the total number be 48.
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First multiply each term by 24(the common denominator found by 8×3) to remove the fractions and make things easier.
24(5) + 24( \frac{x - 2}{3} ) = 24( \frac{x + 3}{8} )
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120 + 8(x - 2) = 3(x + 3)
Then just continue to simplify and isolate the variable.
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x =  - 19

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