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Ugo [173]
3 years ago
6

What is the intensity of a sound with a measured intensity level of 84 db? (i0 = 10-12 w/m2)?

Physics
1 answer:
Ivahew [28]3 years ago
7 0
The unit measurement for sound can be expressed in terms of intensity and in decibels. The intensity of sound is the measure of its power over unit area. The common unit of measurement is in decibels. This is commonly used in measuring the extent of noise. The conversion from intensity to the decibel unit is through logarithmic function. The formula is:

dB = 10 log(I/I0), where I0 is 10^-12 Watts per square meter

Substituting the values to the equation,

84 = 10log(I/10^-12)
I = 0.0002512 W/m2

In scientific notation the intensity is 2.512 x 10^-4 W/m^2.
You might be interested in
Which type of reaction does this diagram represent?
Sever21 [200]

Nuclear fusion because atomic nuclei combine to form a heavier nucleus. Option A is correct.

<h3>What is nuclear fusion?</h3>

The process by which two or more tiny nuclei unite to generate a bigger nucleus is known as a nuclear fusion reaction.

The more energy it takes to liberate an electron from a smaller atom. This is referred to as binding energy.

As a result, when two little nuclei fuse together, there is more binding energy than when two big nuclei fuse together.

For example, the fusion of two hydrogen atoms produces more energy than the fusion of one helium atom, and surplus energy is expelled into space upon binding.

Nuclear fusion because atomic nuclei combine to form a heavier nucleus.

Hence, option A is correct.

To learn more about nuclear fusion refer to the link;

brainly.com/question/14019172

#SPJ1

8 0
2 years ago
When you irradiate a metal with light of wavelength 433 nm in an investigation of the photoelectric effect, you discover that a
sergij07 [2.7K]

Answer:

The right solution is:

(a) 2.87 eV

(b) 1.4375 eV

Explanation:

Given:

Wavelength,

= 433 nm

Potential difference,

= 1.43 V

Now,

(a)

The energy of photon will be:

E = \frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}

  = 4.59\times 10^{-19} \ J

or,

  = \frac{4.59\times 10^{-19}}{1.6\times 10^{-19}}

  = 2.87 \ eV

(b)

As we know,

⇒ Vq=\frac{hc}{\lambda}-\Phi_0

By substituting the values, we get

⇒ 1.43\times 1.6\times 10^{19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}-\Phi_0

⇒                       \Phi_0=2.3\times 10^{-19} \ J

or,

⇒                            =\frac{2.3\times 10^{-19}}{1.6\times 10^{-19}}

⇒                            =1.4375 \ eV

5 0
3 years ago
2. A girl whose mass is 55kg stands on a spring weighing machine inside a lift. When the lift starts to ascend, its acceleration
Annette [7]

Answer:

b

Explanation:

5 0
3 years ago
A 50.0 kg crate is pulled 375 N of force applied to a rope. The crate slides without friction.
LUCKY_DIMON [66]

Hi there!

We can use the work-energy theorem to solve.

Recall that:

\large\boxed{W = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2}

The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:

W = \frac{1}{2}(50)(5.61^2) = 786.8025 J

Now, we can define work:

\large\boxed{W = Fdcos\theta}}

Now, plug in the values:

786.8025 = Fdcos\theta\\\\786.8025 = (375)(3.07)cos\theta

Solve for theta:

cos\theta = .6834\\\theta = cos^{-1}(.6834) = \boxed{46.887^o}

4 0
2 years ago
How does the Doppler effect cause a siren's pitch to increase as it
Likurg_2 [28]

Answer:

Sound waves are pushed closer together, decreasing wavelength

and increasing frequency.

5 0
3 years ago
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