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Lady bird [3.3K]
2 years ago
15

3+2⋅[(2+1)⋅5+8] need the answer please

Mathematics
2 answers:
s2008m [1.1K]2 years ago
8 0

Hey!

----------------------------------------------

Solution:

Remember to follow PEMDAS!

= 3 + 2 ⋅ [(2 + 1) ⋅ 5 + 8]

= 3 + 2 ⋅ [(3) ⋅ 5 + 8]

= 3 + 2 ⋅ [(15) + 8]

= 3 + 2 ⋅ [23]

= 3 + 46

= 49

----------------------------------------------

Answer:

49

----------------------------------------------

Hope This Helped! Good Luck!

ExtremeBDS [4]2 years ago
4 0

Answer:

49

Step-by-step explanation:

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Answer:

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3 years ago
How do you find the end behavior?
Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

In this lesson, you will learn what the "end behavior" of a polynomial is and how to analyze it from a graph or from a polynomial equation.

What's "end behavior"?

The end behavior of a function

f

ff describes the behavior of the graph of the function at the "ends" of the

x

xx-axis.

In other words, the end behavior of a function describes the trend of the graph if we look to the right end of the

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xx-axis (as

x

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+

∞

+∞plus, infinity) and to the left end of the

x

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−∞minus, infinity).

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y=f(x)

x gets

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For example, consider this graph of the polynomial function

fff. Notice that as you move to the right on the x

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ff goes up. This means, as x

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5 0
3 years ago
Find all pairs of natural numbers which can be the solution to the equation a+b=42.
Setler [38]

Answer:

(1,41), (2,40), (3,39), (4,38), (5,37), (6,36), (7,35), (8,34), (9,33), (10,32), (11,31), (12,30), (13,29), (14,28), (15,27), (16,26), (17,25), (18,24), (19,23), (20,22), (21,21), (22,20), (23,19), (24,18), (25,17), (26,16), (27,15), (28,14), (29,13), (30,12), (31,11), (32,10), (33,9), (34,8), (35,7), (36,6), (37,5), (38,4), (39,3), (40,2), (41,1).

Step-by-step explanation:

To find all pairs of natural numbers which are solution to a+b=42, we need to first choose a value to one of them (let's choose 'a'), and that value will be the lowest possible, so we begin with a=1, and then we increase to 2, and 3, and so on.

For each value of a, we calculate the value of b using the equation.

So, starting with a=1, we have that b=41

Then, with a=2, we have that b=40, and so on.

Doing this until a=41 (so b=1 will be the lowest value possible for b), we have the pairs of natural number we want:

(1,41), (2,40), (3,39), (4,38), (5,37), (6,36), (7,35), (8,34), (9,33), (10,32), (11,31), (12,30), (13,29), (14,28), (15,27), (16,26), (17,25), (18,24), (19,23), (20,22), (21,21), (22,20), (23,19), (24,18), (25,17), (26,16), (27,15), (28,14), (29,13), (30,12), (31,11), (32,10), (33,9), (34,8), (35,7), (36,6), (37,5), (38,4), (39,3), (40,2), (41,1).

5 0
2 years ago
How do you solve <img src="https://tex.z-dn.net/?f=3%5E%7Bx%7D%20%3D%20%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="3^{x} = \f
madam [21]

3 to the 2nd power would be 9… so to make it a -9 or 1/9 it would be 3 to the -2nd power

5 0
2 years ago
Read 2 more answers
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