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kolbaska11 [484]
3 years ago
14

Least common multiple of two numbers one of the numbers is seven less than the other number what are the numbers? Justify your a

nswer.
Mathematics
1 answer:
solong [7]3 years ago
5 0

Let x represent the first number, then x-7 represents the second number

Assume the numbers are whole numbers (no negative numbers), then the smallest value that x could be is 8. Thus, the first number is 8 and the second number is 1. The LCM is 8.

Let's increase x by one number so that x=9, then the second number is 2. The LCM is 18.

Let's increase x again by one number so x=10, then the second number is 3. The LCM is 30.

You could continue this to discover that the LCM will be x(x-7) between x=8 and x=13.

So what happens at x=14? First digit is 14 and the second digit is 7. The LCM is 14.

This will occur for all x-values that are multiples of 7.

Answer: when x is a multiple of 7, the LCM is x. when x is not a multiple of 7, the LCM is x(x-7).

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A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

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The vertices are:

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Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

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