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kolbaska11 [484]
2 years ago
14

Least common multiple of two numbers one of the numbers is seven less than the other number what are the numbers? Justify your a

nswer.
Mathematics
1 answer:
solong [7]2 years ago
5 0

Let x represent the first number, then x-7 represents the second number

Assume the numbers are whole numbers (no negative numbers), then the smallest value that x could be is 8. Thus, the first number is 8 and the second number is 1. The LCM is 8.

Let's increase x by one number so that x=9, then the second number is 2. The LCM is 18.

Let's increase x again by one number so x=10, then the second number is 3. The LCM is 30.

You could continue this to discover that the LCM will be x(x-7) between x=8 and x=13.

So what happens at x=14? First digit is 14 and the second digit is 7. The LCM is 14.

This will occur for all x-values that are multiples of 7.

Answer: when x is a multiple of 7, the LCM is x. when x is not a multiple of 7, the LCM is x(x-7).

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The two-way table shows the estimated number of students who will enroll in three area high schools next year. a 5-column table
mr Goodwill [35]

Answer:

A. 0.2

Step-by-step explanation:

First make the table.

                                          <u>10-grade</u>  <u>11-grade</u>  <u>12-grade</u>  <u>Total</u>

<u>Woodson high school </u>    |     110     |     120    |      80     |   310   |

<u>Valley high school </u>          |     180    |     150    |     120     | 450   |

<u>Riverside high school </u>     |     160    |     140    |     200    | 500   |

<u>Total </u>                                 |     450   |     410    |     400    | 1260 |

Question: In decimal form, to the nearest tenth, what is the probability that a randomly selected riverside high school student is in twelfth grade?

First, find 12-grade and riverside high school number. 200. Take the total lined up with total number, which is 1260, and divide 200 divided by 1260.

200/1260=0.2

The answer is 0.2.

Hope this helps!

If not, I am sorry.

6 0
2 years ago
Which is a correct definition of perpendicular lines?
djyliett [7]
It would be B: a set of points that extends infinitely in two directions
4 0
2 years ago
Heather is 5 feet 7 inches tall. There are
lisabon 2012 [21]
Heather is about 167.5 cm

5’7” is equal to 67 inches
when you multiply 67 inches by 2.5 cm (which is around 1 inch) you get 167.5cm
5 0
3 years ago
Read 2 more answers
Find the equation of the circle: y-intercepts 4 and –8, contain (–12, –8)
laila [671]

Answer:

  (x +6)^2 +(y +2)^2 = 72

Step-by-step explanation:

The given points are vertices of a right triangle. The circle circumscribing that triangle (through all 3 vertices) will have its center at the midpoint of the hypotenuse:

  ((0, 4) +(-12, -8))/2 = (-6, -2)

The equation of a circle with center (h, k) through point (a, b) is ...

  (x -h)^2 +(y -k)^2 = (a -h)^2 +(b -k)^2

For center (-6, -2) and point (0, 4), the equation is ...

  (x +6)^2 +(y +2)^2 = (0+6)^2 +(4 +2)^2

  (x +6)^2 +(y +2)^2 = 72

6 0
3 years ago
The repair cost of a Subaru engine is normally distributed with a mean of $5,850 and a standard deviation of $1,125. Random samp
Yuri [45]

Answer:

C. $5180

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Z-scores lower than -2 or higher than 2 are considered unusual.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random normally distributed variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 5850, \sigma = 1125, n = 20, s = \frac{1125}{\sqrt{20}} = 251.56

Which of the following mean costs would be considered unusual?

We have to find the z-score for each of them

A. $6350

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{6350 - 5850}{251.56}

Z = 1.99

Not unusual

B. $6180

Z = \frac{X - \mu}{s}

Z = \frac{6180 - 5850}{251.56}

Z = 1.31

Not unusual

C. $5180

Z = \frac{X - \mu}{s}

Z = \frac{5180 - 5850}{251.56}

Z = -2.66

Unusual, and this is the answer.

3 0
3 years ago
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