<span>They allow us to see distant objects as they were long in the past.
-The further we look into space the further back we look in time.</span>
The line width is calculated as 121.6nm
Data;
- Wave length = 393.3nm
- T1 = 3000k
- T2 = 12,000K
<h3>Rydberg's Formula</h3>
This is used to calculate the wavelength of an electron when it moves from one state to another.
For Lyman series, n = 1
The energy difference in the two state transitioning are
= ∞
The formula is given thus;
R = Rydberg's constant
Z = atomic number
Since the excited electron dropped from the 1st state to the ground state, the finest line of Lyman series would be
The line width is calculated as 121.6nm
Learn more Lyman series here;
brainly.com/question/5295294
To solve the problem it is necessary to take into account the concepts related to frequency depending on the wavelength and the speed of light.
By definition we know that the frequency is equivalent to,
where,
c= Speed of light
While the wavelength is equal to,
Where,
L = Length
n = Number of antinodes/nodes
PART A) For the first part we have that our wavelength is 110MHz, therefore
Therefore the distance between the nodal planes is 1.36m
PART B) For this part we need to find the Length through the number of nodes (8) and the wavelength, that is,
Therefore the length of the cavity is 10.90m
Answer:
B. the object doesn't move.
Answer:
The focal length of the lens is 5.54 cm and the height of the image is -0.89 cm.
Explanation:
Given that,
Height of object h = 2 cm
Object distance u= -18 cm
Image distance v= 8 cm
We need to calculate the focal length of the lens
Using formula of lens
Where, f = focal length
Put the value into the formula
(II). We need to calculate the height of the image
Using formula of magnification
Put the value into the formula
Hence, The focal length of the lens is 5.54 cm and the height of the image is -0.89 cm.