Answer: Your question is missing below is the question
Question : What is the no-friction needed speed (in m/s ) for these turns?
answer:
20.1 m/s
Explanation:
2.5 mile track
number of turns = 4
length of each turn = 0.25 mile
banked at 9 12'
<u>Determine the no-friction needed speed </u>
First step : calculate the value of R
2πR / 4 = πR / 2
note : πR / 2 = 0.25 mile
∴ R = ( 0.25 * 2 ) / π
= 0.159 mile ≈ 256 m
Finally no-friction needed speed
tan θ = v^2 / gR
∴ v^2 = gR * tan θ
v = √9.81 * 256 * tan(9.2°) = 20.1 m/s
Answer:
The final speed of the train and Bambi after collision is 7.44 m/s
Explanation:
Given;
mass of the train, m₁ = 1000kg
mass of Bambi, m₂ = 75kg
initial speed of the train, u₁ = 8 m/s
initial speed of Bambi, u₂ = 0 m/s
If Bambi gets stuck to the front of the train, then the collision is inelastic.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
v is the final speed of the train and Bambi after collision
Substitute the given values and solve for v
1000 x 8 + 75 x 0 = v (1000 + 75)
8000 = v (1075)
v = 8000/1075
v = 7.44 m/s
Therefore, the final speed of the train and Bambi after collision is 7.44 m/s
Given parameters:
Initial volume = 75cm³
New volume = 30cm³
New pressure = 110Pa
Unknown:
Initial pressure = ?
Solution:
Condition: temperature is constant
We simply apply Boyle's law to this problem:
" the volume of a fixed mass(mole) of a gas varies inversely as the pressure changes if the temperature is constant".
Mathematically;
P₁ V₁ = P₂ V₂
where P and V are pressure and volume values
1 and 2 are the initial and final states.
Input the parameters and solve for P₁;
P₁ x 75 = 110 x 30
P₁ = 44Pa
The initial pressure is 44Pa
An example is a car going 100 mph
