Answer:
A True ( I Think Its True I'm Not Intirely sure)
Explanation:
A car with two people traveling down the road has a mass of 100 kg and a velocity of 5 m/s. The car pulls over and picks up two
2 answers:
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Answer:
Check the explanation
Explanation:
Their is no data provided for the mass and length of pendulum in the picture.but it is very easy to check kinetic energy.KE is mv^2/2, m is the pendulum Bob and v is time dependent ,equation of displacement of SHM is given as x(t)=Asin(wt+∆) where ∆ is the phase angle now v=dX/dt _v=Awcos(wt+∆) and KE=
Thus w angular frequency of oscillation is√(g/l)
g acceleration due to gravity and l length of pendulum.so KE is same for pendulum having same mass and length otherwise KE expression with time will vary for all other cases.now check if all experiment pendulum have same mass and length otherwise KE will not be same.You can now easily verify.
Answer:
(a) reaction at each front wheel is 5272N (upward)
(b) force between boulder and pallet is 4124N (compression)
Explanation:
Acceleration of the truck = 1 m/
(to the left)
when the truck moves 1 m to the left, the boulder is B and pallet A are raised 0.5 m, then,
= 0.5 m/
(upward) ,
= 0.5 m/
(upward)
Let T be tension in the cable
pallet and boulder: ∑fy = ∑(fy)eff = 2T- ( +
)g = (
+
)
= 2T- (400 + 50)*(9.81 m/) = (400 + 50)*(0.5 m/
)
T = 2320N
Truck: = ∑(
)eff: =
(3.4m) +
(2.0m) - T (0.6m)=
(1.0m)
Nf = (2.0m)(2000 kg)(9.81 m/ )/3.4m - (0.6 m)(2320 N)/3.4m + (1.0 m)(2000 kg)(1.0 m/
) = 11541.2N - 409.4N - 588.2N = 10544N
∑fy (upward) = ∑(fy)eff: +
-
g = 0
10544 + - (2000kg)(9.81 m/
) = 0
= 9076N
∑fx (to the left) = ∑(fx)eff: - T =
= 2320N + (2000kg)(9.81 m/
) = 4320N
(a) reaction at each front wheel:
1/2 (upward): 1/2 (10544N) = 5272N (upward)
(b) force between boulder and pallet:
∑fy (upward) = ∑(fy)eff: +
g -
= (400kg)(9.81 m/
) + (400kg)(0.5 m/
) = 4124N (compression)