Answer:
a = v²/r
Explanation:
The acceleration of a body moving in a circular path is known as the centripetal acceleration. This is the acceleration of a body that keeps the body within the circular path. It is written in terms of the linear velocity v and the radius of the circle of rotation as shown;
a = v²/r where
v is the linear velocity
r is the radius
a is the centripetal acceleration
The experiments will involve two billiard balls of known masses, m₁ and m₂, and velocities u₁ and u₂. The two are allowed to collide and the velocities of the balls after the collision v₁ and v₂ are recorded.
The momentum before and after the collision is then calculated as follows:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
<h3>What is the statement of the law of conservation of momentum?</h3>
The law of the conservation of momentum states that the momentum before and after collision in a system of colliding bodies is conserved
The momentum of a body is calculated using the formula below:
Momentum = mass * velocity.
Hence, for the two billiard balls, the momentum before and after the collision is conserved.
Learn more about momentum at: brainly.com/question/1042017
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Microscopes with life science and physics
Answer:
The ball will fall on the X .
Explanation:
At height, when the aeroplane is in great speed , everything attached with it acquires the same speed . So ball will also have the same speed as the aeroplane have. When ball starts falling off , it gets detached from plane but , at the same time it continues to travel with its earlier speed , because of inertia of motion. So it remains stationary with respect to plane in horizontal direction . It has velocity with respect to plane only in vertical direction. Hence it will fall on the X. It is due to first law of motion.
