Answer:
50 m/s opposite direction to the motion of the truck
Explanation:
From the question,
Applying the law of conservation of momentum
mu+m'u' = V(m+m')...….. Equation 1
Where m = mass of the truck, u = initial velocity of the truck, m' = mass of the car, u' = initial velocity of the car, V = Final velocity after collision
Given: m = 2500 kg, u = 20 m/s, m' = 1000 kg, V = 0 m/s (both car stop after collision)
Substitute these values into equation 1
2500(20)+1000(u') = 0(2500+1000)
2500(20)+1000(u') = 0
Solve for u'
u' = -[2500(20)]/1000
u' = -50 m/s
The negative sign shows that the car travels in opposite direction to the truck
Hence the car initial velocity before collision is 50 m/s in opposite direction to the motion of the truck
Yes it is possible. Momentum is calculated by the mass of the object times its velocity.
For example, say a bowling ball weighs 3.0kg and is travelling at a speed of 3.0m/s. Its momentum would be 3.0×3.0=9.0 kg·m/s.
Now say we have a baseball weighing 0.20kg and it is travelling at a speed of 47.0m/s. Its momentum would be 0.20×47.0=9.4 kg·m/s, which is more than that of the bowling ball.
Answer:
The magnitude of the electric field is 
Explanation:
Given that,
Time t = 2.10 s
Speed = 160 m/s
Specific charge =Ratio of charge to mass = 0.100 C/kg
We need to calculate the acceleration
Using equation of motion

Put the value into the formula


We need to calculate the magnitude of the electric field
Using formula of electric field



Put the value into the formula


The direction is upward.
Hence, The magnitude of the electric field is 
Answer:
a. the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon; the force is 1.38 × 10⁸ greater than muon
Explanation:
F= ma
v²=u² -2aS
(1.56 ✕ 10⁶)²=(2.40 ✕ 10⁶)²-2a(1220)
a=1.36×10⁹m/s²
recall
F=ma
F = 1.88 ✕ 10⁻²⁸ kg × 1.36×10⁹m/s²
F= 2.55 × 10⁻¹⁹N
the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon
F/mg= 2.55 × 10⁻¹⁹/ (1.88 ✕ 10⁻²⁸ × 9.8)
= 1.38 × 10⁸