Step-by-step explanation:
This seems to be calculus 1.
<u>Question a</u>
We have 
m = slope = derivative
Find the derivative / slope of 
We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.


when x = a
<em>Now that we have this information, we can answer question b</em>
<u>Question b</u>
<u>The tangent line for Point (1, 12)</u>
First find the slope by using our derivative.

Now that we have our slope, use point slope form to find our tangent line


<u>Now lets do the same for the Point (2, 13)</u>
Find the slope at the point.
Now find the tangent line using point slope form of a line.


Now graph the lines, which I have done and you can see by viewing the image I have attached.
Answer:
weshdfiuashfiHFEhihidohfoiehfoih;ehfehfuhfhhosdhh
Step-by-step explanation:
hope this helped :)
Theres a site called desmos that graphs stuff for you
D) 35
Use the slope formula
(y2-y1)
______
(x2-x1)
(70-35)
______= 35/1
(1 - 0)
Answer:
Rs 120.
Step-by-step explanation:
10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price
-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2
[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2
0.75[CP+10]=0.85[CP-2]
0.75CP+7.5=0.85CP-1.7
0.85CP-0.75CP=-1.7–7.5=9.2
0.10CP=9.2; CP=9.2/0.10
CP=Rs 92 Cost Price of pen
10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)
From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92
Set CP of Eq 1=CP of Eq 2:
CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;
0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12
0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)
Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.