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3 years ago

Conventionalcurrent flows form? To?

1 answer:

4 0

"Conventional" current is the way we understood and labeled electrical current before we discovered that the actual charge carriers (electrons) carry negative charge.

The electrons ... doing all of the actual work to make current ... flow from the negative terminal of the power source to the positive terminal, but we still give them no respect. Wherever the direction of current is shown on a schematic diagram, it's "conventional" current. It begins at the positive terminal of the power source, and at every point in the circuit, flows toward places that are more negative.

Conventional current flows from positive to negative.

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a mass of 1.00 kg of water at temperature T is poured from a height of 0.100 km into a vessel containing water of the same tempe

Mariana [72]

Answer:

1.34352 kg

Explanation:

$m_w$ = Mass of water falling = 1 kg

h = Height of fall = 0.1 km

$\Delta T$ = Change in temperature = 0.1

c = Specific heat of water = 4186 J/kg K

g = Acceleration due to gravity = 9.81 m/s²

$m_v$ = Mass of water in the vessel

Here the potential energy will balance the internal energy

$m_wgh=m_wc\Delta T+m_vc\Delta T\\\Rightarrow m_v=\dfrac{m_wgh-m_wc\Delta T}{c\Delta T}\\\Rightarrow m_v=\dfrac{m_wgh}{c\Delta T}-m_w\\\Rightarrow m_v=\dfrac{1\times 9.81\times 100}{4186\times 0.1}-1\\\Rightarrow m_v=1.34352\ kg$

Mass of the water in the vessel is 1.34352 kg

6 0

3 years ago

What items can be classified as matter?

Agata [3.3K]

Gas , Liquid , or solid

7 0

4 years ago

A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa

AVprozaik [17]

To solve this problem it is necessary to take into account the concepts related to the magnetic moment and the torque applied over magnetic moments.

For the case of the magnetic moment of a loop we have to,

$\mu = IA$

Where

I = Current

A = Area of the loop

Moreover the torque exerted by the magnetic field is defined as,

$\tau = IAB$

Where,

I = Current

A = Area of the loop

B = Magnetic Field

PART A) First we need to find the perimeter, then

$P = 2\pi r$

$r = \frac{P}{2\pi}$

$r = \frac{1.9}{2\pi}$

$r = 0.3025m,$

The total Area of the loop would be given as,

$A = \pi r^2$

$A = \pi 0.3025^2$

$A = 0.287m^2$

Substituting at the equation of magnetic moment we have

$\mu = (16*10^{-3})(0.287)$

$\mu = 4.58*10^{-3} A.m^2$

Therefore the magnetic moment of the loop is $4.58*10^{-3}Am^2$

PART B) Replacing our values at the equation of torque we have that

$\tau = IAB$

$\tau = (16*10^{-3})(0.287)(0.790)$

$\tau = 3.62*10^{-3}Nm$

Therefore the torque exerted by the magnetic field is $3.62*10^{-3}Nm$

6 0

3 years ago

Which energy transfer occurs when a cube of ice is placed in a glass of<br> water?

Daniel [21]

Acetic acid is a weak acid and sodium hydroxide is strong base. Salts of the two will hydrolyse to give basic solution. So, at neutral point, pH of the solution will be greater than 8.

5 0

3 years ago

The final position minus the initial position is the

ycow [4]

Answer:

Displacement.

Explanation:

The change in between the starting position (initial position) and your final position is the amount of distance you <em>actually </em>traveled.

For example, you can use a triangle. The distance you travel for side length a & b is equal to the distance you travel on side c (the hypotenuse). You are pretty much solving for the hypotenuse in this case, or the displacement.

6 0

4 years ago

Read 2 more answers