Question

A strong electromagnet produces a uniform magnetic field of 1.60 T and a cross-sectional area of 0.200 m2. If we place a coil having 240 turns and a total resistance of 21.0 around the electromagnet and then we then smoothly reduced the current in the electromagnet until it reaches zero in 20.0 ms, what is the current induced in the coil

Answer 1

Answer:

the magnitude of the induced current is 182.86 A.

Explanation:

Given;

number of turns, N = 240 turns

cross sectional area of the loop, A = 0.2 m²

uniform magnetic field strength, B = 1.6 T

resistance of the loop, R = 21 ohms

time, Δt = 20.0 ms

The magnitude of the induced emf is calculated as;

$emf = \frac{NA B}{t} \\\\emf = \frac{240 \times 0.2 \times 1.6}{20 \times 10^{-3}} \\\\emf = 3,840\ V$

The induced current in the loop is calculated as;

$I = \frac{emf}{R} \\\\I = \frac{3840}{21} \\\\I= 182.86 \ A$

Therefore, the magnitude of the induced current is 182.86 A.