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2 years ago

Of the 5000 species of mammals, 250 species are carnivorous. What is the ratio of carnivorous to mammals?

Physics

1 answer:

Mekhanik [1.2K]2 years ago

4 0

Answer: The ratio of carnivorous species to all mammal species is 1:20

Explanation:

250:5000 = 250/250 = 1

250:5000 = 5000/250 = 20

Answer = 1:20

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A car drives around a curve with a radius of 42 m at a velocity of 24 m/s. What is the centripetal acceleration of the car?

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3 years ago

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Which statement correctly differentiates between transmitters and receivers?

jeka94

Answer:

Transmitters send radio waves, and receivers capture radio waves.

Explanation:

Let us look at each of the choices one by one:

(1).Transmitters have antennas, and receivers do not have antennas.

Nope. To send signals transmitters need antennas, and to receive signals the receivers need antennas as well.

(2). Transmitters send radio waves, and receivers capture radio waves.

This is true. Transmitters are for transmitting and receivers are for receiving EM signals.

(3). Transmitters have demodulators, and receivers have modulators.

No, it is the other way around. Transmitters have modulators, and receivers have demodulators.

(4). Transmitters do not have amplifiers, and receivers have amplifiers.

Nope. Both the transmitters and the receivers need amplifiers. Transmitters need them to increase the power of the broadcast, and receivers need them to amplify the signal for processing.

Therefore, only the 2nd statement "Transmitters send radio waves, and receivers capture radio waves." is correct.

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3 years ago

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An object has a mass of 6kg. calculate it's gpe

m_a_m_a [10]

Explanation:

When m=mass

G=acceleration due to gravity

H=height

Using formula

Mgh

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6×10×h

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3 years ago

A force acts on a 9.90 kg mobile object that moves from an initial position of to a final position of in 5.40 s. Find (a) the wo

horrorfan [7]

Given that,

Mass of object = 9.90 kg

Time =5.40 s

Suppose the force is (2.00i + 9.00j + 5.30k) N, initial position is (2.70i - 2.90j + 5.50k) m and final position is (-4.10i + 3.30j + 5.40k) m.

We need to calculate the displacement

Using formula of displacement

$s=r_{2}-r_{1}$

Where, $r_{1}$ = initial position

$r_{2}$ = final position

Put the value into the formula

$s= (-4.10i + 3.30j + 5.40k)-(2.70i - 2.90j + 5.50k)$

$s= -6.80i+6.20j-0.1k$

(a). We need to calculate the work done on the object

Using formula of work done

$W=F\cdot s$

Put the value into the formula

$W=(2.00i + 9.00j + 5.30k)\cdot (-6.80i+6.20j-0.1k)$

$W=-13.6+55.8-0.53$

$W=41.67\ J$

(b). We need to calculate the average power due to the force during that interval

Using formula of power

$P=\dfrac{W}{t}$

Where, P = power

W = work

t = time

Put the value into the formula

$P=\dfrac{41.67}{5.40}$

$P=7.71\ Watt$

(c). We need to calculate the angle between vectors

Using formula of angle

$\theta=\cos^{-1}(\dfrac{r_{1}r_{2}}{|r_{1}||r_{2}|})$

Put the value into the formula

$\theta=\cos^{-1}\dfrac{(-4.10i + 3.30j + 5.40k)\cdot(2.70i - 2.90j + 5.50k)}{7.54\times6.778})$

$\theta=79.7^{\circ}$

Hence, (a). The work done on the object by the force in the 5.40 s interval is 41.67 J.

(b). The average power due to the force during that interval is 7.71 Watt.

(c). The angle between vectors is 79.7°

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3 years ago

A force of 10N is required to stretch a spring from 20cm to 25cm. What is the spring constant in N/m2 Be careful of unit

kupik [55]

Answer:

C) 40 N/m

Explanation:

If we ASSUME that the spring is un-stretched at the zero cm position

k = F/Δx = 10/0.25 = 40 N/m

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3 years ago