Answer:
So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3
Answer:
it's B. circuit a and b are series circuit while c is parallel
Examples:
<span>Air </span>
<span>Blood </span>
<span>Mouthwash </span>
<span>Rubbing Alcohol </span>
<span>Peroxide </span>
<span>Hand-sanitizer </span>
<span>Perfume </span>
<span>Some bath gels </span>
<span>Coffee </span>
<span>Chicken or Beef Broth </span>
<span>Body Spray </span>
<span>Natural Oils </span>
<span>A heterogeneous mixture is a mixture where the components of the mixture are not uniform or have localized regions with different properties. </span>
<span>Examples: </span>
<span>Rocks </span>
<span>Oil and water </span>
<span>Soup </span>
<span>Pizza </span>
<span>Copper sulfate </span>
<span>Salsa </span>
<span>Chicken soup </span>
<span>Cottage cheese
hope that helped</span>
Answer:
Magnets come in a variety of shapes and one of the more common is the horseshoe (U) magnet. The horseshoe magnet has north and south poles just like a bar magnet but the magnet is curved so the poles lie in the same plane. The magnetic lines of force flow from pole to pole just like in the bar magnet.
1) In the first case, the correct answer is
<span>A.Wavelengths measured would match the actual wavelengths emitted.
In fact, the stars are not moving relative to Earth, so there is no shift in the measured wavelength.
2) In this second case, the correct answer is
</span><span>A.Wavelengths measured would be shorter than the actual wavelengths emitted.
</span>in fact, since the stars in this case are moving towards the Earth, then apparent frequency of their emitted light will be larger than the actual frequency, because of the Doppler effect, according to the formula:

where f0 is the actual frequency, f' the apparent frequency, c the speed of light and vs the velocity of the source (the stars) relative to the obsever (Earth). Vs is negative when the source is moving towards the observer, so the apparent frequency f' is larger than the actual frequency f0. But the wavelength is inversely proportional to the frequency, so the apparent wavelength will be shorter than the actual wavelength.