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liq [111]
3 years ago
6

What did the zeros of the function f(x)=x^3+6x^2+8x

Mathematics
1 answer:
eimsori [14]3 years ago
4 0

Answer:

0,2,4

Step-by-step explanation:

you are going to need to factor all the way down then set each set of parenthesis equal to zero and solve.

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Match each power of a power expression with its simplified expression.
VARVARA [1.3K]

Answer:

> (4^6)^{-3} = \frac{1}{4 ^ {18}}

> (4^{-3})^{-3} = 4 ^ 9

> (4^0)^{-9} = 4 ^0

> (-4^{-9})^2 = (-4) ^ {-18}

Step-by-step explanation:

We have to expand the powers of each of them:

> (4^6)^{-3} = 4^{(6 * -3)}

          = 4 ^ {-18}

(4^6)^{-3} = \frac{1}{4 ^ {18}}

> (4^{-3})^{-3} = 4 ^ {(-3 * -3)}

  (4^{-3})^{-3} = 4 ^ 9

> (4^0)^{-9} = 4 ^ {(0 * -9)}

  (4^0)^{-9} = 4 ^0

> (-4^{-9})^2 = -4 ^ {( -9 * 2)}

  (-4^{-9})^2 = -4 ^ {-18}

8 0
3 years ago
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Two numbers have a difference of 8 what is the minimum product of these numbers
Nady [450]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
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Use partial quotient 28 divided by 514
Ann [662]
The result is 18 r 10
5 0
3 years ago
Solve for x <br> x over 7 = 6
Karo-lina-s [1.5K]

Answer:

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Step-by-step explanation:

What divided by 7 equals 6..... 42! to prove we are right let us plug it into our equation.

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DING DING DING Correct !

7 0
2 years ago
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It's from the chapter : "exponents and powers"<br>i need the workings too<br>please help​
labwork [276]

Answer:

505/19

Step-by-step explanation:

Easy

so [3^3-(1/2)^(-3)*(1/19)]

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(27*19)/19-8/19

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(27*19-8)/19

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Have a wonderful day ask me if you have more questions about MATH that goes for anyone who needs math help

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3 years ago
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