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Andrews [41]
3 years ago
7

A rabbit can run at a speed of 35 mph. This is 7/9 of the fastest speed of an elk. How fast can an elk run?

Mathematics
2 answers:
mafiozo [28]3 years ago
4 0

Answer:

speed of the elk = 45 miles per hour

Step-by-step explanation:

A rabbit speed is around 35 miles per hour. The fastest speed of an elk is 7/9 of the rabbit speed .  

The speed of the rabbit is the 7/9 of the fastest speed of the an elk. The speed of the elk can be computed as follows:

speed of the elk = 35 ÷ 7/9

speed of the elk = 35 × 9 / 7

speed of the elk = 315/7

speed of the elk = 45 miles per hour

Anuta_ua [19.1K]3 years ago
3 0

Answer:

45 miles per hour

Step-by-step explanation:

Divide 35 by 7 and multiply by 9

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How do you write 6.359 × 10^-14 in standard form?
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It is generally claimed that the average body temperature for healthy human adults is 98.6°F. To test this claim a simple random
Rzqust [24]

Answer:

Explained below.

Step-by-step explanation:

The information provided is as follows:

\mu=98.6^{o}F\\\bar x=98.1^{o}F\\s=0.9^{o}F\\n=9

(1)

A single mean test is to be performed in this case.

As the population standard deviation is not provided, a one-sample <em>t</em>-test will be used.

The correct option is b.

(2)

The null hypothesis is:

<em>H</em>₀: The average temperature in the population is 98.6°F, i.e. <em>μ </em>= 98.6°F.

The correct option is b.

(3)

The alternative hypothesis is:

<em>Hₐ</em>: The average temperature in the population is less than 98.6°F, i.e. <em>μ </em>< 98.6°F.

The correct option is c.

(4)

The standard deviation of the sample mean is as follows:

SD_{\bar x}=\frac{s}{\sqrt{n}}=\frac{0.9}{\sqrt{9}}=0.3^{o}F

Thus, the value of SD is 0.3°F.

(5)

Compute the value of test statistic as follows:

t=\frac{\bar x-\mu}{SD_{\bar x}}

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Thus, the value of test statistic is -1.67.

(6)

The degrees of freedom of the test are:

df = n - 1

   = 9 - 1

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Thus, the degrees of freedom of the test is 8.

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