The equation of the line is y = -11x + 232
<h3>How to determine the equation?</h3>
The given parameters are:
Slope (m)= -11
Point (x1, y1) = (31, -109)
The linear equation is then calculated as:
y = m(x - x1) + y1
This gives
y = -11(x - 31) - 109
Evaluate the product
y = -11x + 341 - 109
Evaluate the like terms
y = -11x + 232
Hence, the equation of the line is y = -11x + 232
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Answer:
82
Step-by-step explanation:
2*5 + 9*8 = 10 + 72 = 82
Answer:
where is the question m8
Step-by-step explanation:
Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time t it takes for the ball to hit the ground, we are looking for the height of the ball when it is on the ground. Of course the height of anything on the ground is 0, so if we set s(t) = 0 and solve for t, we will find our answer.
and factor that however you are currently factoring in class to get that
t = -.71428 seconds or
t = 1.42857 seconds (neither one of those is rational so they can't be expressed as fractions).
We all know that time will never be a negative value, so the time it takes this ball to hit the ground is
1.42857 seconds (round how you need to).
Answer:
x = 6
Step-by-step explanation:
PR / RQ = P'R' / R'Q'
x / 9 = 10 / 15
cross-multiply:
15x = 90
x = 90/15
x = 6
