All categories

4 years ago

1. if √16 = x, then x^2

1 answer:

4 0

1. A squares and square root cancels

2. CE square root of a perfect square is rational square root of non perfect squares are irrational

4. ✓16=4 ✓9 =3 therefore ✓10 will be between 4 and 3 which is 3.1 answer is C

You might be interested in

Cant figure this out

Snezhnost [94]

Answer: y^2 / p^3

Step-by-step explanation:

3 0

3 years ago

Can someone explain this

hodyreva [135]

Answer:

x² = V19²-10²

= V361-100

= V261

x = 16.2

3 0

3 years ago

A bag of snacks contains 3 flavors: cherry, lemon, and grape. Carol will take 1 snack from the bag without looking. The probabil

Ronch [10]

Least likely - lemon
Middle - cherry
Most likely - grape

3 0

2 years ago

What is the solution set of the equation using the quadratic formula? x2+6x+10=0 {−3+2i,−3−2i} {−6+2i,−6−2i} {−3+i,−3−i} {−2i,−4

olga2289 [7]

Answer:

The solution set of the quadratic function $x^{2}+6\cdot x +10$ is $\{-3+i,-3-i\}$ .

Step-by-step explanation:

Let be a second-order polynomial (quadratic function) is standard form and equalized to zero:

$a\cdot x^{2}+b\cdot x + c = 0$

Its roots can be determined by the Quadratic Formula in terms of its polynomial coefficients, which states that:

$x_{1,2} = \frac{-b\pm\sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}$

Given that $a = 1$ , $b = 6$ and $c = 10$ , the roots of the polynomial are, respectively:

$x_{1,2} = \frac{-6\pm \sqrt{6^{2}-4\cdot (1)\cdot (10)}}{2\cdot (1)}$

$x_{1,2} = -3\pm i$

$x_{1} = -3+i$

$x_{2} = -3 -i$

The solution set of the quadratic function $x^{2}+6\cdot x +10$ is $\{-3+i,-3-i\}$ .

8 0

3 years ago

Simplify the following expression:<br><br> 6(3x) − 2y + 3z + 12(4x) − 9y

Slav-nsk [51]

Answer:

9x+48x-2y-9y +3z

57x -11y +3z

4 0

3 years ago