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3 years ago

Marc showed 7 with this addition sentence 7=3+3+1. Use marc’s way to show these odd numbers with addition sentences . 5=

Mathematics

1 answer:

Doss [256]3 years ago

3 0

The answer is: 5=3+1+1

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What is the equation written in vertex form of a parabola with a vertex of (–1, 8) that passes through (1, 0)?

Archy [21]

Answer:

y = -2(x + 1)^2 + 8

Step-by-step explanation:

The equation of a parabola can be written in the form;

y = a(x-h)^2 + k

where a is the multiplier (h,k) is the vertex

so h = -1 and k = 8

Plug in these values

y = a(x + 1)^2 + 8

So to get the value of a, we use the point where the parabola passes through which is the point (1,0)

Simply substitute the values of x and y

0 = a(1 + 1)^2 + 8

0 = a(2)^2 + 8

-8 = 4a

a = -8/4

a = -2

So therefore the equation of the parabola is ;

y = -2(x + 1)^2 + 8

7 0

3 years ago

What is 285.39154 rounded to the nearest hundredth

svp [43]

285.39 I belive the awsner is

3 0

4 years ago

Read 2 more answers

What is the volume of the oblique cube

serious [3.7K]

Answer:

$\large\boxed{V=\dfrac{1600\pi}{3}\ cm^3}$

Step-by-step explanation:

The formula of a volume of a cone:

$V=\dfrac{1}{3}\pi r^2H$

r - radius

H - height

We have r = 10cm and H = 16cm. Substitute:

$V=\dfrac{1}{3}\pi(10^2)(16)=\dfrac{1}{3}\pi(100)(16)=\dfrac{1600\pi}{3}\ cm^3$

6 0

3 years ago

A firm has the marginal-demand function where D(x)=-1400x÷√25-x² is the number of units sold at x dollars per unit. Find the dem

borishaifa [10]

The equation of the demand function is D(x) = 1400√(25-x²) + 11400

<h3>How to determine the demand function?</h3>

From the question, we have the following parameters that can be used in our computation:

Marginal demand function, D'(x) = -1400x÷√25-x²

Also, we have

D = 17000, when the value of x = 3

To start with, we need to integrate the marginal demand function, D'(x)

So, we have the following representation

D(x) = 1400√(25-x²) + C

Recall that

D = 17000 at x = 3

So, we have

17000 = 1400√(25-3²) + C

Evaluate

17000 = 5600 + C

Solve for C

C = 17000 - 5600

So, we have

C = 11400

Substitute C = 11400 in D(x) = 1400√(25-x²) + C

D(x) = 1400√(25-x²) + 11400

Hence, the function is D(x) = 1400√(25-x²) + 11400