complete question:
If the height and base of the parallelogram shown are each decreased by 2 cm, what is the area of the new parallelogram?
A parallelogram with a base of 10 centimetres and a height of 8 centimetres.
Answer:
area = 48 cm²
Step-by-step explanation:
A parallelogram is quadrilateral with 4 sides formed by 2 pair of parallel lines. The area of a parallelogram is represented as follows :
area of parallelogram = B × H
where
B = breadth
H = height
According to the question the height and the base each reduced by 2 cm.
The new base = 10 - 2 = 8 cm
The new height = 8 - 2 = 6 cm
area = B × H
area = 8 × 6
area = 48 cm²
So for this you would have to use the pythagorean theorem which is α²+b²=c². The 12 yards would be a and the distance between the 60 yard line and 50 yard line which is 5 would be b and you would be trying to find out what c is.
a²+b²=c²
12²+5²=c²
144+25=c²
169=c²
now you want to get c alone and in order to do that we would square root it and i'm sure you have learned that what you do on one side you have to do to the other so we would also square root 169
√169=√c²
13=c
the pass was 13 yards
hope i helped :)
Answer:
3. x=90
6. X= 180-120
X=60
Step-by-step explanation:
hope this helps
Answer:
11
Step-by-step explanation:
Look at the picture for the process.
- 4 - 4 + 4 ÷ 4
- 4 ÷ 4 + 4 ÷ 4
- (4 + 4 + 4) ÷ 4
- √4 + √4 + 4 - 4
- √4 + 4 + 4 ÷ 4
- √4 + 4 + 4 - 4
- 4 + 4 - 4 ÷ 4
- 4 + 4 + 4 - 4
- 4 + 4 + 4 ÷ 4
- √4 + √4 + √4 + 4
- 44/(√4 + √4)
- √4 + √4 + 4 + 4
- 44/4 + 4
- 4 + 4 + 4 + √4
- 44/4 + 4
- 4 * 4 * 4 ÷ 4
- 4 * 4 + 4 ÷ 4
- 4 * 4 - √4 + 4
- 4! - 4 - 4 ÷ 4
- 4 * (4 + 4 ÷ 4)
- 4! - 4 + 4 ÷ 4
- 4 * 4 + 4 + √4
- 4! - √4 + 4/4
- 4 * (√4 + √4 + √4)
- 4! + √2 - 4 ÷ 4
- 4! + √4 + 4 - 4
- 4! + √4 + 4 ÷ 4
- 4! + 4 + 4 - 4
- 4! + 4 + 4 ÷ 4
- 4! + √4 + √4 + √4
Lol, that took a while, hope it helps!
