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valentinak56 [21]
3 years ago
13

10.63 divided by 10 please answer

Mathematics
2 answers:
olganol [36]3 years ago
7 0
Well you would move the decimal over 1 more space to the right. As decimals are powers of 10s. so 1.063
vladimir1956 [14]3 years ago
5 0
The answer is: 1.036.

Hopefully this helps! :)
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I am 64 inches tall to the nearest inch,<br> What is the error interval for my height?
Scrat [10]

Answer:

2345678879ft

Step-by-step explanation:

s w2y6w45uwsati0ywpoe978 r9we7r 09wer978we90r78w9e80rfseupoifjsd

8 0
3 years ago
A quiz-show contestant is presented with two questions, question 1 and question 2, and she can choose which question to answer f
Mrrafil [7]

Answer:

The contestant should try and answer question 2 first to maximize the expected reward.

Step-by-step explanation:

Let the probability of getting question 1 right = P(A) = 0.60

Probability of not getting question 1 = P(A') = 1 - P(A) = 1 - 0.60 = 0.40

Let the probability of getting question 2 right be = P(B) = 0.80

Probability of not getting question 2 = P(B') = 1 - P(B) = 1 - 0.80 = 0.20

To obtain the better option using the expected value method.

E(X) = Σ xᵢpᵢ

where pᵢ = each probability.

xᵢ = cash reward for each probability.

There are two ways to go about this.

Approach 1

If the contestant attempts question 1 first.

The possible probabilities include

1) The contestant misses the question 1 and cannot answer question 2 = P(A') = 0.40; cash reward associated = $0

2) The contestant gets the question 1 and misses question 2 = P(A n B') = P(A) × P(B') = 0.6 × 0.2 = 0.12; cash reward associated with this probability = $200

3) The contestant gets the question 1 and gets the question 2 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.4×0) + (0.12×200) + (0.48×300) = $168

Approach 2

If the contestant attempts question 2 first.

The possible probabilities include

1) The contestant misses the question 2 and cannot answer question 1 = P(B') = 0.20; cash reward associated = $0

2) The contestant gets the question 2 and misses question 1 = P(A' n B) = P(A') × P(B) = 0.4 × 0.8 = 0.32; cash reward associated with this probability = $100

3) The contestant gets the question 2 and gets the question 1 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.2×0) + (0.32×100) + (0.48×300) = $176

Approach 2 is the better approach to follow as it has a higher expected reward.

The contestant should try and answer question 2 first to maximize the expected reward.

Hope this helps!!!

3 0
2 years ago
when a study is designed so that neither the subjects nor the experimenters know which subjects are in the treatment group and w
Nata [24]
(taken from a source)

<span>double blind
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Hope this helped!

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5 0
3 years ago
Read 2 more answers
Evaluate and answer in standard form:<br><br>4^2/3^2​
Semenov [28]

the answer is : 1.7777

6 0
3 years ago
10. Mr. Guerrero left his house and drove north at an average speed of 40 mph.Two hours later, his daughter Miranda left the hou
Charra [1.4K]
Speed=distance / time  ⇒ distance=time x speed
distance=d
time=t
speed= s

d=s*t

Distance  traveled by Mr Guerrero, when his daugther left the house
Data:
s=40 miles/ hour
t=2 hours
d=40 miles/ hour * 2 hours=  80 miles

Total distance traveled by Mr Guerrero:
d=80 miles + 40 miles/hourt    ⇒d=80+40t      (1)

d=total distance.
s=speed.
t=time spent by Miranda for she overtook her father.

Distance traveled by Miranda.
data:

s=48 miles/ hour
d=total distance.
t=time spent by Miranda for she overtook her father.

d=48 miles/hour * t      ⇒d=48t       (2)

With the equations (1) and (2), we make an system of equations:

d=80+40t
d=48t

We can solve this system of equation by equalization method.

80+40t=48t
80=48t-40t
80=8t
t=80/8=10

d=48t
d=48*10=480

Answer: the thistance will be 480 miles.
3 0
3 years ago
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