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gavmur [86]
3 years ago
11

Find the coordinates of the image of R (2, 1) after the translation (x, y) → (x, y − 5).

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

(2,-4)

Step-by-step explanation:

We subtract 5 to the y-coordinate, so we have (2,-4)

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Order the following from least to greatest.<br>1/16<br>.0173<br>1/7<br>2.2<br>-0.25​
Dovator [93]

Answer:

1.-0.25     2..0173   3. .1/16    4. 1/7     5.2.2

Step-by-step explanation:

You want to put all numbers in fractions to see which numbers are smallest

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Distrubutive property 4(c+d+9)
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Answer:

4c+4d+36

Step-by-step explanation:

multiply each separate variable inside the parenthesis by the number outside of parenthesis.

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3 years ago
Factor this expression 27 + 33
Yuri [45]
3(9+11)
Your welcome =)
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3 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

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