Question

To practice catching, the little

Answer 1

The height of the  ball after 2 seconds is 36 units

Solution:

The pathway  of the ball from the machine can  be represented by the equation:

$h = -16t^2 + 48t + 4$

To find: height of the  ball after 2 seconds

Substitute t = 2 in above equation

$h = -16(2)^2 + 48(2) + 4\\\\h = -16 \times 4 + 96 + 4\\\\h = -64 + 100\\\\h = 36$

Thus the height of the  ball after 2 seconds is 36 units